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Implement full subtractor with two half subtractors and OR gate?
Wiki User
∙ 12y ago
You use the first HS with entries of x0 and y0 . then you get D0=X0 XOR Y0
and B0=X0 NOT*Y0.(*=AND)
Then you use the sacond HS with entries of D0(from the first HS) and B-1(borrow from the previous level). then you get D1=X0 XOR Y0 XOR B-1(exactly like D in FS)
and B1=D0 NOT*B-1.
Then you use the OR gate with entries B0(from the first HS) and B1(from the second HS) and you get B=B0 OR B-1 AND D0 NOT. If you check the options you can get their similar to the borrow of FS
Wiki User
∙ 12y ago
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A+b=
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gate in full
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Wants the meaning
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Minimum number of and gates required to form full and half adder?
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