No. The way this is worded all x are y but not all y are necessarily x.
.
Example:
All Gorillas are Apes.
Some Apes are Chimpanzees.
Some Gorillas are Chimpanzees. (Not True)
.
All Dogs are Mammals.
Some Mammals are Cats.
Some Dogs are Cats. (Not True)
.
Analysis:
All A are B.
Some B are C.
Therefore, Some A are C.
.
∀x(Ax → Bx)
∃x(Bx ∧ Cx)
∴ ∃x(Ax ∧ Cx)
Truth Tree
..............................|Bn ET(n)
..............................|Cn ET(n) premise
............................./.\
.........................../....\
.......UT prem ~An / ......\
........................../\........\
......................../..\.........\
UT neg con ~An /.....\ ~Cn \ Bn UT prem
.............invalid ↑..... ↑...... /\
...................................../...\
.............................~An /......\ ~Cn UT negative conclusion
...................................↑.......x Invalid
Ignore the periods. The spaces were being deleted so I included periods to make the truth tree readable.
The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----
x2-y2=(x-y)(x+y) which is a well known identity.
y =x^2-x-56 is the same as y = (x + 7)(x - 8)
2 * 7 * x * x * y
Greater than x or y (?)
It is logically valid but not grammatically.
-8
Equality is a binary relationship, defined on a set S, with the following properties:Reflexivity: x = x for all x in the set S.Symmetry: if x = y then y = x for all x, y in S.Transitivity: if x = y and y = z then x = z for all x, y and z in S.
The properties of multiplication need to be considered in the context of the set over which this operation is defined.For most number systems, multiplications isCommutative: x*y = y*x for all x and yAssociative: (x*y)*z = x*(y*z) so that , without ambiguity the expression can be written as x*y*z for all x, y and zDistributive property over addition or subtraction:x*(y+z) = x*y + x*z for all x, y and zIdentity Element: There exists a unique element, denoted by 1, such that1*x = x = x*1 for all xZero element: there is an element 0, such that x*0 = 0 for all x.In some sets, an element x also has a multiplicative inverse, denoted by x-1 such that x*x-1 = x-1*x = 1 (the identity).
Let x, y, and a be sets and X,Y,x',y' be elements. Denote X *x as X in (is an element of) x, I as intersection, and U as union. If we can show that for all X *x, X *y (and similarly, if for all Y *y, Y *x), then we are done. Case 1) xIa is empty Then x, a and y, a have no elements in common. So, if xUa and yUa are equal, then for all y' *yUa but y' not*a, y' *y. Since xUa and yUa are equal, either y' *a or y' *x. But we supposed y' is not*a, so y'*x. Similarly, for all x' *x, x'*y. QED Case 2) xIa is non-empty Define a' as a - {x| x *xIa}. Then xIa' is empty, and you can use the same prove as above, replacing a with a'. QED
No. In fact, under normal rules of operation, x-y equals y-x only when x = y.
The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.
The union of sets X and Y is the set consisting of all elements that belong to X, or belong to Y or to both.The union of sets X and Y is the set consisting of all elements that belong to X, or belong to Y or to both.The union of sets X and Y is the set consisting of all elements that belong to X, or belong to Y or to both.The union of sets X and Y is the set consisting of all elements that belong to X, or belong to Y or to both.
Yes, y =5 is a constant function. Meaning that for any value of x (in the domain), the value of the function (y) is 5. The graph would be a horizontal line five units above, but parallel to, the x-axis. Another answer: The above comments are only valid if we specify that x is just some constant. In general, however, when we refer to the function y=f(x)=x we do not mean a constant function, but rather a diagonal line running through the origin. The function would be a constant function if it were y=f(x)=c for some c, but normally when we write y=x we mean that the value of y is the value of x, and hence y changes as x changes.
All points with x and y that are both non-zero!All points with x and y that are both non-zero!All points with x and y that are both non-zero!All points with x and y that are both non-zero!
(x + y) / (x-1 + y-1) = (x + y) divided by ( 1/x + 1/y)Multiply numerator and denominator by 'xy' :xy (x + y) / (y + x)Then the whole thing falls apart, and we're left with:xy
There are infinitely many rules. SOme of these are: y = x/80 y = 80/x y = x + 79 y = 81 - x y = sqrt(x+1) - 8