No, the complement of real numbers is not a binary operation. A binary operation requires two elements from a set to produce a new element within the same set. The complement of the set of real numbers typically refers to elements not included in that set, which does not satisfy the criteria of producing a new element within the set of real numbers.
N-P = 0. Note here that N is the set of Natural numbers, P is the set of positive integers, and - is the set operation that in the above statement implies N and P are the same, with the exception that 0 is an element of N but not of P.
It is not valid, till 2005, certificates ( All Degrees) issued by this university are valid, Later, the certificates issued by this university is not valid
Yes, It was approved by HRD and UGC. But Supreme Court dnotified the operation of all the Private Universities in the year 2005. So If any one had Certificates that got till 2006, as government and university challenged the order to save careers of students till last session by 2006 is valid
It is a operation on the brain
A set is not an operation.
yes
Yes, that is a perfectly valid mathematical operation.
SOME meter must be your mombile or her
It is not defined because division by 0 is not a valid operation
operation set
operation set
Because multiplication is a binary operation that is defined so that it is valid for all numbers.
Presumably, yes! A redundant operation, but valid all the same.
A set is a set and does not need an arithmetic operation.
The law of closure states that a set of numbers is closed under an operation if when the operation is performed on any two elements of the set the result is an element of the set
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