It ia really easy it is 8
We know that f:A~B is a bijection Therefore f^-1:A~B is a unique function To prove that f^-1 is one-one-- Let b1, b2 be any 2 different elements of B ,, i.e b1 is unequal to b2 Now we have to prove that f^-1(b1) is unequal to f^-1(b2) Let f^-1(b1)=a1. And. f^-1(b2)=a2 Such that a1,a2 €A Then b1= f(a1) and b2=f(a2) ~f^-1(b1) is unequal to f^-1(b2) Therefore f^-1 is a one-one function Now f^-1 has a n image a such that b€B Therefore f^-1 is onto function Finally f^-1 is a bijection Hence proved
b2 is slightly bigger
The discriminant of the quadratic equation ax2+bx+c = 0 is the value of b2-4ac When b2-4ac = 0 then there are 2 equal roots. When b2-4ac > 0 then there are 2 different roots. When b2-4ac < 0 then there are no roots at all.
b2 bakugan r evoltions of a bakugan 4 example: Drago > meteor drago
An A1 sheet measures 594 x 841 mm, while an A4 sheet measures 210 x 297 mm. To determine how many A4 sheets fit into an A1, you can divide the area of the A1 sheet by the area of the A4 sheet. This calculation shows that 8 A4 sheets can fit into one A1 sheet.
To show all possible interleavings of two processes, let’s assume we have two atomic statements from Process A (A1, A2) and Process B (B1, B2). The possible interleavings could be: A1, A2, B1, B2 A1, B1, A2, B2 B1, A1, A2, B2 A1, B2, A2, B1 B1, B2, A1, A2 B2, A1, A2, B1 A2, A1, B1, B2 B2, B1, A1, A2 These interleavings illustrate the various ways the two processes can be executed in a concurrent setting.
6 cells. They are A1, A2, A3, B1, B2 and B3.
Yes. Vectors follow the same laws as simple scalars. For example A + B = C ; (A1 + A2) + (B1 +B2) = (A1 + B1) + (A2 + B2) = C1 + C2 where C1 = A1 + B1 and C2 = A2 + B2.
I think you probably mean "range" instead of "ranch". In Excel, a range is a group of cells. A range can be as small as a single cell (for example, cell A1), block of cells (example, A1:B2), or even non-contiguous cell (example: A1,B2,C3). It could also be an entire column (A:A) or row (1:1). In the A1:B2 example above, this range would include four cells A1, A2, B1, and B2
You could use either of the following, by putting the formulas in any cells except A1 and B1: =A1+B1 =SUM(A1:B1)
Vectors are added by components; z1 + z2 = a1 + ib1 +a2 +ib2 = (a1 + a2) + i (b1 + b2)
a1/a2 is not equal to b1/b2
A1-B3-A3-B2-A2-B1
Suppose you have two sets of n-numbers: {a1, a2, a3, ... , an} and {b1, b2, b3, ... , bn} Then the form for the standard sum of product is a1*b1 + a2+b2 + a3*b3 + ... + an*bn
a1 = b1 = c1 a2 = b2 = c2
The answer is 14 if u mean like a1 b2 c3 d4 .....
To add vectors on the same line, simply add their components together. If you have two vectors represented as (a1, a2) and (b1, b2), their sum would be (a1 + b1, a2 + b2). This is known as the component method of vector addition.