Since The vectored Location of RST5.5 lie in Half the location of RST5 and RST6 so it is called RST 5.5(RST 5+1/2 )
Explanation:
Vector Interrrupt Vectored Location
RST 5 0028H
RST 5.5 002CH
RST 6 0030H
Now we add RST5 and RST6 vectored Location's
0028H + 0030H = 0058H
Now Devide The Sum by 2
0058H/2 = 002CH
Which is Vectored Location of RST 5.5.
This You can Check for All other vectored Interrupts TRAP(RST4.5), RST6.5, RST7.5
for 8085 Microprocessor
Thanks .............. S C Patidar
answer is = 55 becouze 11=11,22,33,44,(55) 5=5,10,15,20,25,30,35,40,45,50,(55)
it significance that the dog is GOD..
Any of its factorrs which are: 1, 5, 11 and 55
Trap is actually a software generated interrupt caused either by an error (for example division by zero, invalid memory access etc.), or by an specific request by an operating system service generated by a user program. Trap is sometimes called Exception. The hardware or software can generate these interrupts. When the interrupt or trap occurs, the hardware therefore, transfer control to the operating system which first preserves the current state of the system by saving the current CPU registers contents and program counter's value. after this, the focus shifts to the determination of which type of interrupt has occured. For each type of interrupt, separate segmants of code in the operating system determine what action should be taken and thus the system keeps on functioning by executing coputational instruction, I/O instruction, torage instruction etc.
Since 55 is a factor of 110, it is automatically the GCF.
An interrupt vector is the memory address of an interrupt handler, or an index into an array called an interrupt vector table or dispatch table. Interrupt vector tables contain the memory addresses of interrupt handlers. When an interrupt is generated, the processor saves its execution state via a context switch, and begins execution of the interrupt handler at the interrupt vector.
"You should not interrupt class," the teacher scolded the boy.
In the 8086/8088, the interrupt vector table is the first 1024 bytes of memory. In the 8085, the interrupt vector table is the first 64 bytes of memory if using the RST form of interrupt, otherwise the interrupt vector is provided by the interrupting device, usually in the form of a CALL instruction. The interrupt handler is wherever the interrupt vector points to.
the prefix of interrupt is in
"Interrupt" is a verb.
RIM stands for read interrupt mask and SIM stands for set interrupt mask.The SIM instruction is used to copy the contents of the accumulator into the interrupt mask.The RIM instruction is used to interpret the RST interrupt positions.
An interrupt is a hardware-generated change of flow within the system. An interrupt handler deals with the cause of the interrupt. Control is then returned to the interrupted context An interrupt is a hardware-generated change of flow within the system. An interrupt handler deals with the cause of the interrupt. Control is then returned to the interrupted context
There are 2 types interrupts in 8085 such as: 1)hardware interrupt 2)software interrupt
VECTOR INTERRUPT If the interrupt is assigned to any predefined branching address to its ISR it is termed as vector interrupt. NON VECTOR INTERRUPT If the interrupt is not assigned to any predefined branching address to its ISR it is termed as non-vector interrupt. PRIYAKRISH
I believe a nested interrupt, is where an interrupt is allowed to occur (and thus is handled) during an already occurring Interupt service ruotine. I.E. First interrupt occurs ISR1 begins second Interrupt occurs ISR2 begins ISR2 Finishes ISR1 continues from where left off ISR1 finishes
The highest priority interrupt in the 8085 is the TRAP interrupt.
The response to another interrupt request during servicing of an interrupt depends on the setting of the interrupt enable flag and/or the interrupt mask. If the interrupt service routine is thread safe, it will process correctly. More probably, problems will arise so the proper procedure is to either set the interrupt mask (8085) to not allow this or lower priority interrupts before reenabling interrupt, or to leave interrupts disabled until this iteration is complete. If interrupts are disabled or masked, a subsequent interrupt will be posted but not processed until the first is completed.