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No its 80' its not exact but maybe .008 inches off
the height is 10669 in feet.! ~sierra
The seismosaurus was roughly 18 feet tall. If you are 6 feet tall, you are 1/3 the height of a seismosaurus.
anybody know what the height of a felmale panda is?
feet and inches
It is 1.6 ft, approx.
If you mean the height of the building then it works out as 466.5063509 feet
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
It should be approximately 1.26 inches, or 1 1/4 inch to the nearest quarter inch. The tangent of an angle of 1 degree is 0.17455 times the 6 foot base is 0.10473 feet.
height = 15 ft base = 20 ft angle of elevation = arctan (15/20) = 36.87 degrees
The answer is 0.33
Tan60= 25/Height. Height = 25/Tan60 = 14.43
The deck height should be 5 feet
If you look up at something and it is at 45 degrees then the distance away from the base is equal to its height. You are 50 feet from the pole.
The leg opposite the 58 degree angle is the height of the kite above the ground. So, the leg is 36 ft.
3.03 feet (rounded)
A degree is a measure of rotation, a foot is a measure of distance. These two are incomparable.