It varies greatly. It will depend on how far away it is from the object it's orbiting. If it is in a circular orbit around the Earth, its speed can be calculated by the formula:
speed = Squareroot(398600/(6371+altitude))
This will give you an answer in kilometers per second.
The massive speed and acceleration of the spaceship is so great, that they are able to escape Earth's gravitational pull. Then at around the correct altitute, they can orbit the Earth safely.
Spaceship Spitzer The Slowlian Web - 2008 was released on: USA: November 2008
BLN
Event Horizion
Apollo 11
3 m/s
2 m/s
3 m/s
2 m/sec in the direction of travel of Spaceship 2, assuming they are both in frictionless outer space.
2,000 kg-m/s
The initial speed of spaceship 1 can be calculated using the formula: initial momentum = mass * velocity. Therefore, the initial speed of spaceship 1 would be 6 m/s.
Momentum = (speed) times (mass).Spaceship-1 has no momentum, since its speed is zero. The combined momentum is just the momentum of Spaceship-2.Momentum of Spaceship-2 = (m V) = 300 x 4 = 1,200 kg-meters
2000
Multiply mass x velocity for each spaceship. Add the results.
1,800 kg-m/s
2,000 kg-m/s
To find the initial speed of spaceship one, we need to apply the principle of conservation of momentum. Since the two spaceships have equal masses, their momenta will be equal and opposite. The momentum of spaceship two is given by 150 kg * V2, where V2 is the initial speed of spaceship two. The momentum of spaceship one is given by 150 kg * V1, where V1 is the initial speed of spaceship one. Since they have equal magnitudes, we have 150 kg * V1 = 900 kg * (-V2). Solving for V1 gives V1 = - 6 V2. Since we want the initial speed in magnitude, the initial speed of spaceship one is 6 times the initial speed of spaceship two in magnitude.