It is ionic bond
Strontium and iodine would form ionic bonds in a compound with formula SrI2.
Strontium, with atomic symbol Sr, would be more like potassium, because both strontium and potassium are active metals and bromine is a nonmetal. The actual element with symbol S is sulfur, and that would be more like bromine, because those elements are both nonmetals.
no ionic strontium is a metal and flourine is a nonmetal
It is ionic as are all strontium compounds.
Strontium. They both have two electrons in their outermost energy level, however since the electrons are farther from the nucleus in Strontium than in Calcium, Strontium is more readily able to shed these two electrons to achieve a more stable state with it's outermost energy level being complete (with 8 electrons).
Strontium and iodine would form ionic bonds in a compound with formula SrI2.
Strontium is closer to potassium because both are metals and belong to s-block of Periodic Table.
To calculate the mass of 1.14x10^24 atoms of iodine, you would first determine the molar mass of iodine (I), which is approximately 126.9 g/mol. Then, you would use Avogadro's number (6.022x10^23 atoms/mol) to find the mass. Therefore, the mass of 1.14x10^24 atoms of iodine would be approximately (1.14x10^24 atoms / 6.022x10^23 atoms/mol) * 126.9 g/mol = 241 grams.
No. However, bromine would displace iodine in potassium iodide.
The formula unit for strontium chloride is StCl2 and therefore contains 3 atoms, one of strontium and two of chlorine.
Iodine has a molar mass of 129.9g So one mol of Iodine is 129.9g. Therefore 10 moles of iodine would be 1299g.
Strontium is an earth metal (element #38), and iodine is a halide non-metal (element #53), therefore they would form an ionic bond. Strontium ions have a +2 charge, and iodines -1, so to form a neutral-charged compound, we need 2 iodines for every Strontium, and the chemical formula would be: SrI2.
The half-life of rubidium-87 is approximately 48.8 billion years. This means it would take about 48.8 billion years for half of the rubidium-87 atoms in a rock sample to decay into strontium-87. Therefore, to see half of the rubidium-87 atoms change into strontium-87, you would need to wait this extensive period.
The stability increases because Iodine has 7 valence electrons but when it bonds with another iodine atom it can share an electron (non polar covalent bond) and fill it's highest sub level making it more stable.
The chemical formula for the combination of strontium and bromine is SrBr2. In this ionic compound, strontium (Sr) has a 2+ charge, while bromine (Br) has a 1- charge, requiring two bromine atoms to balance the charges.
Strontium, with atomic symbol Sr, would be more like potassium, because both strontium and potassium are active metals and bromine is a nonmetal. The actual element with symbol S is sulfur, and that would be more like bromine, because those elements are both nonmetals.
A nucleophilic substitution reaction would take place, replacing various numbers of chlorine atoms with iodine atoms. Thus a mixture of compounds is produced.