Do you mean why is the voltage in a circuit lower after the light bulb than before it? If so, it's because the light bulb filament has electrical resistance. When an electrical current flows through a resistance, there is a voltage drop across the resistance (Ohm's law).
More fundamentally, the light bulb is producing light, which is a form of energy. The voltage drop across the light bulb comes from the fact that electrical energy is being turned into light. If voltage didn't drop, you would be producing energy from nothing. Furthermore, if there were no voltage drop, your circuit would behave the same whether you had no light bulbs, one light bulb, or eighteen million light bulbs - something that clearly can't be the case.
electricity because a light bulb needs electricity
They both produce light, they run on electricity, they're made out of glass and they contain argon under low pressure. Fluorescent lights are better because they last longer and are more energy efficient! :) -kelly.t (:
When a light bulb is rated for 3.2 V it means that it is the maximum operating voltage to be applied to the bulb.
lioght
yes
A voltage is applied across the terminals of the light fixture to which the bulb is attached by two terminals, hot and neutral. A current then flows through the bulb. In an incandescent light the filament wire heats up and glows.
argon
Electricity flows through the path of least resistance. Electricity will flow through anything conductive; metals, liquids, and even through small particles. Your insulators are porcelain, glass, plastics, wood and cloths. All variances of voltage is deadly. The most dangerous thingabout electricity is the current or amperage. As little as 17 miliamps can stop your heart.
A light bulb in an electric circuit when electricity reaches it.
kinetic energy and light energy.
Heat, which then produces light.
A closed current
Some is changed into light and heat energy and some continues through the curcuit
Incandescence. The filament is heated by the electricity moving through it, this causes the filament to heat up, and the heat causes the familiar glow.
Simply put, no. A light bulb lights up because the filament inside (the thin wire that often breaks) has a lot of resistance in it, then when electricity flows through it, it heats up and glows brightly.
Electricity flows through the filament, resistance in the filament causes heat and light energy to be created.
Nowhere. That's why the light goes out. Switching a light switch off breaks the circuit, and without a complete circuit, no electricity flows through the lamp.