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As the load current increases the losses in the circuit increases (I2R loss) and speed of the generator decreases so the voltage falls a little. and this voltage fall can be adjusted by increasing the speed of the generator and Iron losses are taken as constant losses.
Wiki User
∙ 13y ago
Wiki User
∙ 12y agoAny resistance in a circuit consumes power (watts) with the formula P=I2R representing this usage. With very small changes in current, since the current is squared in the formula, the power consumed by the circuit increases geometrically. When this power is consumed in the conductors you have "voltage drop," which gives you less voltage at the load. You should not be able to read this difference at the source, only at the load, or somewhere in between, and only when the load is in operation.
P is power or watts.
I is current and stands for intensity. Why I don't know.
R is resistance.
Alternative AnswerWhile the above answer explains why a voltage drop should exist across a load, it doesn't really answer the question posed.All sources of emf, such as batteries and generators, have an internal resistance (in the case of generators, this is due to the resistance of its windings). As the load current increases, the resulting internal voltage drop (across its internal resistance) also increases, leaving less voltage across the source's terminals.
A source's electromotive force only appears across its terminals when no load current is drawn -hence the corresponding term 'no-load voltage'. Whenever a load is attached, the higher the internal voltage drop the lower the resulting terminal voltage:
i.e. terminal voltage = (emf .) - (internal voltage drop)
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How does a voltage regulator regulate the voltage output of an ac generator?
Generator output is controlled by voltage feedback to the voltage regulator which senses voltage drop or rise and regulates the current being sent to the armature. This rise and fall of the armature current governs the generators output voltage.
Why secondary terminal voltage decreases with increase in load?
An increase in load (equivalent to a decrease in resistance*) causes an increase in load current. This increases the internal voltage drop within the transformer, and the terminal voltage reduces accordingly.[*An increase in load means more current is being drawn by that load, so an increase in load is equivalent to a decrease in load resistance]
What is the difference between voltage output of a battery and the voltage across each DC bulb in a series circuit?
Exactly...you answered your own question. Each DC bulb will drop voltage according to its resistance and the amount of current it draws.
If the resistance in the circuit is increased what will happen to the current and voltage?
* resistance increases voltage. Adding more resistance to a circuit will alter the circuit pathway(s) and that change will force a change in voltage, current or both. Adding resistance will affect circuit voltage and current differently depending on whether that resistance is added in series or parallel. (In the question asked, it was not specified.) For a series circuit with one or more resistors, adding resistance in series will reduce total current and will reduce the voltage drop across each existing resistor. (Less current through a resistor means less voltage drop across it.) Total voltage in the circuit will remain the same. (The rule being that the total applied voltage is said to be dropped or felt across the circuit as a whole.) And the sum of the voltage drops in a series circuit is equal to the applied voltage, of course. If resistance is added in parallel to a circuit with one existing circuit resistor, total current in the circuit will increase, and the voltage across the added resistor will be the same as it for the one existing resistor and will be equal to the applied voltage. (The rule being that if only one resistor is in a circuit, hooking another resistor in parallel will have no effect on the voltage drop across or current flow through that single original resistor.) Hooking another resistor across one resistor in a series circuit that has two or more existing resistors will result in an increase in total current in the circuit, an increase in the voltage drop across the other resistors in the circuit, and a decrease in the voltage drop across the resistor across which the newly added resistor has been connected. The newly added resistor will, of course, have the same voltage drop as the resistor across which it is connected.
What is the phase relationship between the input and output voltage of a common emitter amplifier?
In common emitter amplifier circuit, input and output voltage are out of phase. When input voltage is increased then ib is increased, ic also increases so voltage drop across Rc is increased. However, increase in voltage across RC is in opposite sense. So, the phase difference between the input and the output voltages is 180 degrees.
How does a voltage regulator regulate the voltage output of an ac generator?
Generator output is controlled by voltage feedback to the voltage regulator which senses voltage drop or rise and regulates the current being sent to the armature. This rise and fall of the armature current governs the generators output voltage.
What is the effect of diode voltage drop as the output voltage?
The effect of diode voltage drop as the output voltage is that the input voltage will not be totally transferred to the output because power loss in the diode . The output voltage will then be given by: vout=(vin)-(the diode voltage drop).
When voltage increase then current will be?
it depends on what type of load. Motor amperage will drop off as voltage rises. loads such as lights will increase amperage with voltage rise.
How do you increase the current produced by coils?
to increase the turn of the coil ANSWER: Nobody can increase the current of a coil it actually losses power because of IR drop. from the source to the final output will always be less unless the current is amplified by an active device like a current amplifier where the power is from another source.
How transistor produce 180 degree phase shift?
In the common emitter configuration, a class A amplifier, an increase in base voltage (the input) leads to an increase in base-emitter current which leads to a proportionately larger increase in base collector current. That pulls the collector towards the emitter, which decreases the collector voltage. Since the collector is the output, this configuration is an inverting amplifier.
Why out put current increase in transformer with capacitance load?
ferranti effect...B.*If we use capacitive load the stator MMF aid the rotor MMF. It means that in times of capacitive load rotor flux and main field flux are additive. So the alternator voltage increase with capacitance loading.[By Akhtaruzzaman08]
Why ce configuration of transistor has a 180 phrase difference in output?
A: As current begins to flow the action on a resistance will be a voltage drop which is inversely proportional to the current. Making it a voltage amplifier as opposed to a tube where it is a current amplifier
Why output voltage increases when capacitive loading is used?
The output voltage do not really increase, it is only the meter reading that increase, because not all meters is true RMS meters. If a true RMS meter is used, the output voltage will read the same with or without a capacitor. A value of .2887 approximately have to be added per volt that is measured on an ordinary meter, the reason for this is that a unsmoothed rectified sine wave is not a pure DC voltage it is a series of half cycles that can be beter explained with a sketch http://www.patenttrade.net/rms.htm
How the current in a circuit changes if the resistance increase and the voltage remains constant?
If the resistance increases, the current diminishes. The voltage may drop a little and the multimeter can't read it or can't accuse so little voltage dropping.
Why secondary terminal voltage decreases with increase in load?
An increase in load (equivalent to a decrease in resistance*) causes an increase in load current. This increases the internal voltage drop within the transformer, and the terminal voltage reduces accordingly.[*An increase in load means more current is being drawn by that load, so an increase in load is equivalent to a decrease in load resistance]
What is effect of voltage and current by changing the length of wire?
By changing the length of wire, say reducing it, the resistance will drop and that will increase current flow but the voltage is less likely to change V=IR.
How do you calculate voltage drop for starting motor current and how to get the starting pf?
How do you calculate voltage drop for starting motor current
