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Q: Why the sum of 60S and 40S is 80S not 100S?
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Why 40S plus 60S equals 80S and not 100S?

It doesn't. Whoever said it was 80S made a mistake, or somebody misstated or misunderstood the question. 100S is the correct sum.


How many positive 3-digit integers can be formed that the 100s digit is equal to the sum of the 10s and 1s digit?

54


How many positive even integers up to 1000 inclusive have an even digit sum?

For single digit numbers in the range 0-9 there are 4 (excludes zero). For 2 digit numbers in the range 10-99, then the even sum condition only applies when both digits are even, i.e. such numbers ending in 0,2,4,6,8 in the 20s, 40s, 60s & 80s. There are 4 x 5 = 20. For 3 digit numbers in the range 100-999 then the even sum condition applies when (1) All 3 digits are even or (2) The first 2 digits are odd and the third digit is even. (1) There are 4 options for the 1st digit (2,4,6,8), and 5 options for the 2nd and 3rd digits (0,2,4,6,8) There are thus 4 x 5 x 5 = 100 qualifying numbers. (2) If the 1st and 2nd digits are odd and the 3rd digit is even then there are 5 x 5 x 5 = 125 qualifying numbers. Total number of qualifying numbers = 4 + 20 + 100 + 125 = 249


How many integers between 300 and 500 have the sum of their digits equal to A?

There are 3 whose sum is 45 whose sum is 57 whose sum is 69 whose sum is 711 whose sum is 813 whose sum is 915 whose sum is 1017 whose sum is 1119 whose sum is 1219 whose sum is 1317 whose sum is 1415 whose sum is 1513 whose sum is 1611 whose sum is 179 whose sum is 187 whose sum is 195 whose sum is 203 whose sum is 211 whose sum is 22.


What is the sum of a pentacontakaipentagon?

A shape does not have a sum. The angles of a shape have a sum, the lengths of its sides have a sum, the number of its diagonals are a sum, but the shape itself certainly does not have any sum!


What is the relationship between the probability of an event and its compliment?

Their sum is 1.Their sum is 1.Their sum is 1.Their sum is 1.


How do you draw a flow chart to find the average of three numbers?

Sum = Sum + first number Sum = Sum + second number Sum = Sum + third number Average = 1/3 x Sum


What is the answer to an addition problem called?

The answer to an addition problem is called the sum.The sum of 2 plus 2 is 4.


What are the divisibility rules for 56?

56 = 7 × 8, thus the number must be divisible by both 7 and 8 - check for each of these digits: 8 is easy to check: add the units digit to twice the tens digit to 4 times the hundreds digit; if this sum is divisible by 8 then so is the original number. There is no easy check for 7. One I can offer: Split the number into blocks of 3 digits starting at the right hand end. Now alternatively subtract and add the each of the digits from the blocks: the units, tens and hundreds digits separately. Finally add the sum of the units digits to 3 times the sum of the tens digits to twice the sum of the hundreds digits; if this sum is divisible by 7, then so is the original number. eg 123456789 → 123 456 789 → sum units: 9 - 6 + 3 = 6 → sum tens: 8 - 5 + 2 = 5 → sum hundreds: 7 - 4 + 1 = 4 → check sum: 6 + 3×5 + 2×4 = 29 29 is not divisible by 7, so 123456789 is not divisible by 7. [The remainder of 29 divided by 7 is 1, so 123456789 divided by 7 has a remainder of 1.] eg is 135792648 divisible by 56? 8 + 2×4+4×6 = 40 which is divisible by 8, so 135792648 is divisible by 8. 135792648 → 135 792 648 → sum units: 8 - 2 + 5 = 11 → sum 10s: 4 - 9 + 3 = -2 → sum 100s: 6 - 7 + 1 = 0 → chk: 11 + 3×-2 + 2×0 = 5 not divisible by 7, so 135792648 is not divisible by 7 Thus 135792648 is not divisible by 56 eg is 63592648 divisible by 56? Divisible by 8 as before: 8 + 2×4 + 4×6 = 40 = 5×8 63 592 648 → sum units: 8 - 2 + 3 = 9 → sum 10s: 4 - 9 + 6 = 1 → sum 100s: 6 - 5 = 1 → chk: 9 + 3×1 + 2×1 = 14 = 2×7 → divisible by 7 → 63592648 is divisible by 56 (63592648 = 113558×56)


When you add two fractions the answer is called?

the sum the sum


If 28 percent of sum is 100.80 what is the sum?

sum=360


Create a program that will display the sum of all numbers from 1 up to the input number?

to print the sum of first ten numbers:- void main() {int i,sum; sum=0; while(i<=10) sum=sum+i; i=i+1; } printf("The sum is : %d",sum); }