Yes
No. The horizontal distance depends on how close the the ground the gun is. From the firing position, a bullet dropped to the ground will strike the ground in the same time as a bullet shot horizontally forward.
Platyypuses are measured in length rather than height. Platypuses are not measured for how tall they are, as they stay close to the ground. At most, they would be less than 20cm (8 inches) in height at the shoulder.
Answerlook at it this way: If I were to say, "I'd prefer to play soccer." It would be correct. If I said, "I'd prefer go bowling." It wouldn't make sense. The sentence would be "I'd prefer to play soccer than to go bowling." Break it up into two separate sentences and it's a lot easier.
If the collision involving the ball hitting the ground was perfectly elastic (the system's energy is conserved) then the ball would return to it's original height. However, this is a "perfect world" situation, since no collision can be completely elastic (except for on the atomic scale, but that is another topic). Energy is lost by the friction of the ground, sound, air resistance etc...
your height would be than 5'2
Assuming both were dropped from the same height above ground, in a vacuum both would hit the ground at the same time. In a significant atmosphere (e.g. average ground-level on Earch) the bowling ball would hit the ground first.
When an object is dropped from a certain height, the time it takes to reach the ground is independent of the height (assuming no air resistance). Therefore, whether you drop the object from three times the initial height or the original height, it will still take the same time (T) to reach the ground.
They would both SPLAT on the ground at the same instant.
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.
True, in a vacuum where there is no air resistance, a tennis ball, a bowling ball, and a feather would hit the ground at the same time when dropped from the same height. This is because all objects fall at the same rate regardless of their mass when only gravity acts upon them. However, in the presence of air, the feather would fall more slowly due to air resistance.
According to the laws of physics they would fall at the same rate and land at the same time. However, all variables are not the same. The lightness of the tennis ball would leave it more apt to be affected by winds aloft, including updrafts. Additionally, the fuzzy covering of the tennis ball would make it subject to more wind resistance than the bowling ball, thereby slowing it down more. They would still strike the ground very close together, but the bowling ball would be first.If, however, a bowling ball and a baseball were dropped from the plane, they would strike the ground more-or-less simultaneously.
In a vacuum, they would hit the ground at the same time due to gravity. However, in the real world with air resistance, the bowling ball would typically hit the ground first because it has more mass and air resistance affects lighter objects more.
No. They will hit the ground at the same time. The inertia for the heavier ball will be greater, but the acceleration for both will be the same, and both would (if the air resistance is the same for both) hit at the same time.
The time it takes for a volleyball to hit the ground when dropped from a height depends on the height it falls from. Using the formula for free fall ( t = \sqrt{\frac{2h}{g}} ), where ( h ) is the height in meters and ( g ) is the acceleration due to gravity (approximately ( 9.81 , m/s^2 )), you can calculate the time. For example, if dropped from 2 meters, it would take about 0.64 seconds to hit the ground.
Discounting any friction with the air, they would both hit the ground at the same time.
Assuming the object is dropped from rest and neglecting air resistance, it would take approximately 7.0 seconds for the object to hit the ground from a height of 500 feet. This is based on the formula t = sqrt(2h/g), where t is the time, h is the height, and g is the acceleration due to gravity (approximately 32.2 ft/s^2).
The ESB is much wider at its base than at its top, so no object dropped from its top would hit the sidewalk. HOWEVER, an object dropped from the height of the ESB would, if it experienced no air friction nor hit anything along the way, would hit the ground in 8.8 seconds. However, air friction would delay this by a few seconds, as a small ball would experience air resistance before that time.