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Q: Can an inground pool be 17 feet deep?

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To calculate the volume of a swimming pool go to the link below.

17*35*5= 2975 cubic feet 1 cubic foot ≈ 7.48 gallons So, 2975 cubic feet ≈ 22253 gallons

28,152 cubic feet

V = 2,269.8 cubic feet.

In a 17 foot by 13 foot pool each foot of depth would contain 1653.08 gallons of water. If the pool had a average depth of 4 feet there would be 4 X 1653.08 or 6612.32 gallons.

17 x 17 = 289 square feet.

I'm guessing the 48 is inches, so it is 4' deep. The volume of the pool would then be 9x17x4 or 612ft3. 1 cubic foot is equal to 7.48 gallons. So 612x7.48 = 4577 gallons.

The volume is 12' x 17' x 4' = 816 cubic feet = 6,104.104 gallons.We have no way to know how much water may be in that volume.It might even be empty.

17 sq ft * 3 in = 17*3/12 cubic ft = 4.25 cu ft. So 6 cu ft will cover it.

The volume of the pool is (13' x 17' x 4') = 884 cubic feet = 6,612.8 gallons. (rounded) We have no way of knowing how much water is in it.

Volume = (length) x (width) x (depth).IF the bottom slopes uniformly ... no flats or sudden drop-offs ... thenwe can use the average depth of (8.5 + 3)/2 = 5.75 feet.Volume = (35) x (17) x (5.75) = 3,421.25 = 25,592.73 gallons (rounded)That would be the volume of the pool, if the bottom slopes uniformly fromone end to the other. I have no way of knowing how much water is in it.

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