It means that the wave (or Object) in reference is repeating itself with the rate of 100 Cycles (or times) per second.
BW = (1 MHz - 10 KHz) = (1,000 KHz - 10 KHz) = 990 KHz
Assuming that the receiver uses a high-side local oscillator and an IF of 455 KHz, the image frequency is 910 KHz above. When tuned to 1600 KHz, the image frequency would be 2,510 KHz.
The local oscillator could be either 1165 KHz (710+455) or 255 KHz (710-455).
Electromagnetic Frequency (EMF) & Radio Frequency (RF)
No higher than 1090 kHz and no lower than 1110 kHz
BW = (1 MHz - 10 KHz) = (1,000 KHz - 10 KHz) = 990 KHz
Assuming that the receiver uses a high-side local oscillator and an IF of 455 KHz, the image frequency is 910 KHz above. When tuned to 1600 KHz, the image frequency would be 2,510 KHz.
If 10 V input causes a frequency shift of 4 kHZ then 2,5v causes a freuency shift of 1 kHz. The input signal frequency of 1 kHz is irelevant.
The period of a waveform is the reciprocal of its frequency. For a clock waveform with a frequency of 500 kHz, the period can be calculated as 1 / 500 kHz = 2 microseconds.
Trovan 128 Khz and ISO 134 Khz
Period = reciprocal of frequency = 1 / (500) = 0.002 second
The maxium frequency swing in FM is ± 75 kHz so 75 kHz x 60% = ± 45 kHz
The standard US AM band is 520 kHz-1,610 kHz. The mean would be at 1,065 kHz.
kHz (kilohertz) is a unit of frequency, not a unit of speed.
The minimum sample rate required to record a frequency of 96 kHz is 192 kHz. This is because according to the Nyquist theorem, the minimum sampling rate must be at least twice the highest frequency in order to accurately reconstruct the original signal. So for a frequency of 96 kHz, the minimum required sampling rate is double, which equals 192 kHz.
20 khz.
38 kHz