36g water contains 12.046 x 1023 molecules.
What an odd question. Well, whatever. The question shows that 1/9 of the solution is hydrogen. So it must be said that 8/9 is water (assuming the sample comprises solely of hydrogen and water)36/9 = 44 x 8 = 32So 32g of it is oxygen.
To find the mass of water decomposed, we first need to calculate the total mass of the products formed, which is 4g (hydrogen gas) + 32g (oxygen gas) = 36g. The original mass of water decomposed is equal to the total mass of products formed, so 36g of water is decomposed.
6,022140857.1023 molecules---------------------------------------------1 mole2.1022 molecules--------------------------------------------------------------x molex = 0,033 moles
The number of water molecules obtained is 120,44281714.10e23.
It enables water molecules to stick to each other and to many other things.
It is 2x6.023 x 1023
3
36g = 1.27oz
it all depends on what element you are talking about
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1 mole of water is 18g. 36g of water is thereforeequivalent to 2 moles. 2 moles of water contains 4 moles of hydrogen and 2 moles of oxygen and so there are6 moles of atoms in 2 moles of water. 6 moles of atoms x (3.6x10^24) = 36.1x10^24 atoms
The answer is 0,166.10e23 molecules.
2.60x10^23 water molecules contain 2.60x10^23 molecules of water.
What an odd question. Well, whatever. The question shows that 1/9 of the solution is hydrogen. So it must be said that 8/9 is water (assuming the sample comprises solely of hydrogen and water)36/9 = 44 x 8 = 32So 32g of it is oxygen.
546 molecules
To find the mass of water decomposed, we first need to calculate the total mass of the products formed, which is 4g (hydrogen gas) + 32g (oxygen gas) = 36g. The original mass of water decomposed is equal to the total mass of products formed, so 36g of water is decomposed.
One is produced