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For an atom with 9 electrons, such as fluorine, the electron configuration would be 1s² 2s² 2p⁵. This means that the first energy level (1s) contains 2 electrons, and the second energy level contains 2 electrons in the 2s subshell and 5 electrons in the 2p subshell. The arrangement reflects the Aufbau principle, where electrons fill the lowest energy orbitals first before moving to higher ones.

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What is the Bohr-Rutherford diagram for fluorine?

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The Bohr-Rutherford diagram of a fluorine atom would show 9 protons and 9 electrons arranged in three energy levels with 2 electrons in the first energy level and 7 electrons in the second energy level. The outer energy level would contain 7 electrons, giving fluorine a full valence shell and making it a reactive nonmetal.


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