A boy dropped a stone in a well 45m deep if the speed of sound is 340m per second then after how much time he willl hear the splash take the g equals 10m per second?

Answer 1

If you mean 'after the splash is seen' then g has nothing to do with this problem; only the speed of sound and the distance.

500/340 =1.47 seconds.

If you want to include the time it takes for the stone to fall then

500 = 1/2x10 t2 t= 10 seconds 10+1.47 = 11.47 seconds

Answer 2

Using the equation for free fall: ( h = \frac{1}{2}gt^2 ), where h is the height, g is acceleration due to gravity, and t is time. By substituting the given values (h = 45m, g = 10 m/s^2), we can solve for time: ( 45 = \frac{1}{2} \times 10 \times t^2 ). This gives us t=3 seconds. Since the sound travels at 340m/s, the boy will hear the splash after 3 seconds + time taken for sound to travel from the bottom of the well to the top, which is 45m/340m/s = 0.132 seconds. Total time = 3.132 seconds.

Answer 3

Velocity= (distance*2)/time 340=(45*2)/t; 340/90=t; t=3.78 seconds