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That depends on several things. Since the object is described as having weight I assume it is stationary on the earths surface but this is really not necessarily the case, if it's on the moon or Mars or even in free fall, despite the reference to weight, these would all alter the initial conditions and hence, the answer. Secondly, what direction is the force acting in. If the object is sitting on the ground or a sturdy table and the force acts downward then the final answer will be zero. If the object is being held up by some not so strong object which will break upon application of this force then the answer depends entirely on how high this apparatus was and could be zero or the result of the combination of gravity plus the 392 Newton force plus the friction with the air if you want to consider that. But what if the new force is not acting down, what if it is acting upward, or sideways or at some angle to be given. These all give very different answers. Sitting here though, I am realizing that there is one general equation or system of equations which would take all of this into account and give you your answer regardless of the different variables. I am too sleepy to work it out right now but it is a fun exercise and I will try to find time to derive it in the next day or so and post it.

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