Xenon difluoride, XeF2. Xenon is a noble gas, and as such has a full outer shell of eight electrons; as per the octet rule, it doesn't usually form chemical bonds. However, highly reactive nonmetals such as fluorine can induce it to do so.
F2ccf2
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There are no lone pairs on the central atom in BCl3 because boron (B) is in group 13 (or 3A) and can have only 3 bonds around it.
BCl3 has a trigonal planar shape, with the boron atom at the center and three chlorine atoms symmetrically arranged around it, each separated by 120 degrees. It only has three electron pairs around the central boron atom, resulting in a flat, triangular molecular geometry.
You need to look at the molecular geometry using VSEPR theory in order to answer this question. If you do so, you'll find that one of the molecules is both planar and symmetric within that plane. That's the non-polar compound. (In other words: I've given you a hint; do your own homework.) the hint is about BCl3 but it has a net dipole so it is also polar.
F2ccf2
No, BCl3 does not follow the octet rule as boron only has 6 valence electrons in this molecule. Boron can form stable compounds with less than an octet due to its electron deficiency.
Yes the sulfur needs to have two more electrons to fill the octet, and chlorine only needs one. So there are two chlorines to give sulfur one electron. The whole molecule is covalently bonded so the electrons are shared between the chlorines and the sulfur so that both the elements octets are filled.
BCL3 is a Lewis acid because it can accept an electron pair from a Lewis base. Boron in BCl3 has an incomplete octet, making it electron deficient and capable of accepting an electron pair to complete its octet, giving it a positive charge.
BCl3 and BEH2 obey the octet rule because Boron and Beryllium are exceptions to the octet rule and can have stable electron configurations with less than 8 electrons. Cl3CF, NO, and SbF5 do not obey the octet rule because they have incomplete or expanded valence shells.
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sp2
The central atom in BCl3 is boron, which has only three valence electrons. Since it forms three bonds with the chlorine atoms, the hybridization of the central boron atom is sp2.
There are no lone pairs on the central atom in BCl3 because boron (B) is in group 13 (or 3A) and can have only 3 bonds around it.
BCl3 has 3 bond pairs. Each chlorine atom forms a single covalent bond with the central boron atom.
I think two elements that does not follow the octet rule are boron and beryllium. These elements always have one electron pair less than normal configuration. Boron is an important element for our body.
BCl3 is the formula for Boron Chloride. As a matter of interest it does not obey the octet rule. It is also called a Lewis Acid.