What is the balanced equation for Ch3COOH alone
CaCO3 + 2 CH3COOH ------------- Ca(CH3COO)2 + H2O + CO2
KI + CH3COOH --> HI + CH3COO-K+ ROOH + 2HI --> ROH + H2O + I2 TITRATION WITH SODIUM THIOSULPHATE TO DERIVE THE PEROXIDE VALUE 2NA2S2O3 + I2 (PURPLE) --> NA2S4O6 + NaI (COLOURLESS)
One example would be: acetic acid and ammonia form ammonium acetate. CH3COOH + NH3 --------> CH3COONH4
CH3CH2OOCCH3 + H2O ===> CH3CH2OH + CH3COOH
Ch3coo(-) + h2o ---> ch3cooh + oh(-)
The balanced chemical equation for the combustion of acetic acid (CH3COOH) is: 2 CH3COOH + 4 O2 → 4 CO2 + 4 H2O
The balanced equation between ethanoic acid (CH3COOH) and methanol (CH3OH) to form methyl acetate (CH3COOCH3) is: CH3COOH + CH3OH -> CH3COOCH3 + H2O.
ch3coona+FECL2
CH3COOH+NH4OH turns into H2O+CH3COONH4 have fun with chem
There is no reaction. Two acids cannot react with each other.
The balanced equation for the reaction between acetic acid (CH3COOH) and sodium hydrogen carbonate (NaHCO3) is: CH3COOH + NaHCO3 -> CH3COONa + H2O + CO2 This reaction produces sodium acetate (CH3COONa), water (H2O), and carbon dioxide (CO2).
Ca + 2HC2H3O2 --> Ca(C2H3O2)2 + H2 submitted by Ethan + JD FTW
CH3COOH+NaHCO3 -> H2O+NaOCOCH3+CO2
The reaction between sodium hydroxide (NaOH) and acetic acid (CH3COOH) forms sodium acetate (CH3COONa) and water (H2O). The balanced chemical equation is: CH3COOH + NaOH -> CH3COONa + H2O.
The reaction equation between CH3CSNH2 and H2O would involve hydrolysis of the amide bond in CH3CSNH2. The products would be CH3COOH (acetic acid) and NH3 (ammonia). The balanced equation is: CH3CSNH2 + H2O → CH3COOH + NH3
NaHCO3 + CH3COOH-------------CH3COONa + CO2 + H2O
CaCO3 + 2 CH3COOH ------------- Ca(CH3COO)2 + H2O + CO2