To calculate the molar conductivity (( \Lambda_m )) of a 1 molar solution of sulfuric acid, you can use the formula:
[ \Lambda_m = \frac{\kappa}{C} ]
where ( \kappa ) is the conductivity (given as ( 26 \times 10^{-2} , \text{S/m} )) and ( C ) is the concentration in molarity (1 mol/L). Therefore,
[ \Lambda_m = \frac{26 \times 10^{-2}}{1} = 26 \times 10^{-2} , \text{S m}^2/\text{mol} ]
Thus, the molar conductivity is ( 0.26 , \text{S m}^2/\text{mol} ).
Molar conductivity at infinite dilution refers to the maximum conductivity of an electrolyte solution when it is extremely dilute. At this limit, all ions are completely dissociated and free to conduct electricity independently. This value is used to compare the conducting abilities of different electrolytes irrespective of their concentrations.
Molar units are siemens per meter per molarity, or siemens meter-squared per mole.Molar conductivity is defined as the conductivity of an electrolyte solution divided by the molar concentration of the electrolyte, and so measures the efficiency with which a given electrolyte conducts electricity in solution.
The term molar it refers a form to know the concentration of a solution, and it is equivalent to a molar unit in a litre of solvent 1 Molar (1M) = 1 mole (molecular weight from the structure you are interested in) / 1000 mL or 1 L. Milimolar is the thousandth part from a solution 1M
The mass of a 10 mmol solution will depend on the molar mass of the solute. To calculate the mass, multiply the number of moles (10 mmol) by the molar mass of the solute in grams/mole.
Initially, the mass of H2SO4 required to prepare 5.8 liters of 1.5 molar solution should be calculated. Number of moles present in 5.8 L of 1.5 molar solution = 1.5 mol L-1 x 5.8 L= 8.7 molMolar mass of H2SO4 = 98 g mol-1Therefore, mass of H2SO4 in the above solution = 8.7 mol x 98 g mol-1= 852.6 gMass of H2SO4 in the original solution per litre = 1.531 g x 32/100= 0.48992 gVolume of sulphuric acid required to prepare 1.5 molar solution = 852.6 g/0.48992 g = 1740.3 L
Molar conductivity is what increases dilution. It is the conductivity of an electrolyte solution.
Molar conductivity at infinite dilution refers to the maximum conductivity of an electrolyte solution when it is extremely dilute. At this limit, all ions are completely dissociated and free to conduct electricity independently. This value is used to compare the conducting abilities of different electrolytes irrespective of their concentrations.
Molar units are siemens per meter per molarity, or siemens meter-squared per mole.Molar conductivity is defined as the conductivity of an electrolyte solution divided by the molar concentration of the electrolyte, and so measures the efficiency with which a given electrolyte conducts electricity in solution.
Molar conductivity typically decreases with increasing concentration due to increased ion-ion interactions at higher concentrations. Additionally, molar conductivity generally increases with temperature due to enhanced ion mobility and decreased viscosity of the electrolyte solution.
Infinite dilution molar conductivity is the limiting value of the molar conductivity as the concentration tends to zero. The molar conductivity of KCl at infinite dilution is approximately 149.9 S cm² mol⁻¹ at 25°C.
To calculate the osmolarity of a solution, you add up the molar concentrations of all the solutes in the solution. This gives you the total number of particles in the solution, which determines its osmolarity.
The molar concentration of the hydrogen ions
To calculate osmolarity in a solution, you add up the molar concentrations of all the solutes present in the solution. This gives you the total number of osmoles per liter of solution, which is the osmolarity.
The term molar it refers a form to know the concentration of a solution, and it is equivalent to a molar unit in a litre of solvent 1 Molar (1M) = 1 mole (molecular weight from the structure you are interested in) / 1000 mL or 1 L. Milimolar is the thousandth part from a solution 1M
The relationship between electrolyte concentration and molar conductivity is that as the concentration of electrolytes increases, the molar conductivity also increases. This is because more ions are available to carry electrical charge, leading to higher conductivity.
The decrease in molar conductivity of weak acids with increasing concentration is due to ion-ion interactions. As the concentration increases, the ions come closer together, leading to more frequent inter-ionic collisions and decreased mobility. This results in a decrease in conductivity.
Well if you have 99% solution of H2SO4, that means of one L you have 990 mL the acid. The density of sulphuric acid is 1.84g/mL... so that means you will have by mass 1821.6g of acid. The molecular weigth of H2SO4 is 98.1g/mol... so if you divide mass by molar mass you should get moles... which is about... 18.57moles. So that means 99% sulphuric acid is approx. 19M.