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Color blindness is an X-linked recessive trait A color-blind man has a daughter with normal color vision She mates with a male who has normal color vision What is the expected phenotypic ratio of t?
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
What is the probability that a color-blind woman will have a color- blind son?
The colorblind woman can pass the allele to all her children including sons and daughters but the daugthers will only be carriers for the trait whereas the sons will produce the trait. In order for the daughter to express the trait they would need the allele not only from the mother but from the father also. I just took an exam on this and got it right.
A color-blind woman mates with a male with normal color vision Which of these results would indicate that color blindness is caused by an X-linked recessive allele?
If the couple has a color-blind son, it would indicate that color blindness is caused by an X-linked recessive allele. This is because sons inherit their single X chromosome from their mother, who carries the recessive allele for color blindness but does not express it due to her second X chromosome providing the normal color vision gene.
How do you show a punnett square of a woman who is color blind and a man who has normal vision?
Colorblindness is a sex-linked trait carried on the X chromosome. Males have an X and a Y chromosome (XY) and females have two X chromosomes (XX). Normal vision is dominant over colorblindness. This means that the man must have an allele for normal vision on his only X chromosome. This also means that the woman must have two colorblind alleles on both of her X chromosomes. If we use a capital 'B' to represent normal vision and a lowercase 'b' to represent colorblindness, the genotype of the male would be XBY, and the genotype of the female would be XbXb. Now that we know the genotypes, setting up the Punnett square should be easy. Here is a direct image link to the Punnett square: http://i.imgur.com/gDfUv.png This Punnett square tells us that there is a 50% chance of having a female that has normal vision and a 50% chance of having a colorblind male.
Is Stephen hawking blind?
No, Stephen Hawking was not blind. He was diagnosed with amyotrophic lateral sclerosis (ALS), which gradually paralyzed him over time, but his vision was not affected.
Can two persons with normal vision produce a colorblind son?
No they will produce a child who is colour blind.
Does a blind spot impair normal vision?
It is not impact our vision.
A male who has normal vision marries a female who is a carrier for colorblindness can they have a colorblind daughter?
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
What is the probability that a woman who is a carrier of the colorblind gene and a color blind man will have a first son who will be color blind?
The probability is 0 (but the daughter will be a carrier of the color blind gene). This is because the gene dictating whether someone is color blind or not is linked to the X chromosome (and not the Y). The color blind gene is a recessive gene whilst the normal color vision gene is a dominant gene. Hence if a girl (XX) has one normal vision gene (from one parent) and one color blind gene (from the other parent), her normal vision gene will be dominant to the recessive color blind gene and hence she will have normal vision (but she will be a carrier of the color blind gene). If both her parents contribute the recessive color blind gene to her, then she will be color blind. For a woman (XX) to be color blind, she needs to be have both genes to be recessive (ie where there is no dominant normal color vision gene to dominate). For a man (XY), as long as the X gene contributed by his mother is a color blind gene, he will be color blind because he has no other X chromosome where a dominant normal color gene could reside. Hence, to answer the question, a man with normal color vision (XY, with a dominant normal color vision X gene since the gene can't be the recessive color blind gene otherwise he will be colorblind) and a colorblind woman (XX, both recessive color blind genes), will each contribute an X each the child. The man will contribute his only X chromosome which carries the normal color vision X gene and the woman can only contribute a recessive color blind gene. The man's normal color vision X gene will be dominant, and hence the daughter will definitely have normal vision (despite being a carrier).
Red-green color blindness is an X-linked recessive trait A woman who has a color-blind mother and a father with normal color vision marries a?
man with normal color vision. Since the woman is a carrier of the red-green color blindness gene (inherited from her color-blind mother), there is a 50% chance that any son they have will be color-blind, as he would inherit the X chromosome with the color-blind gene from his mother. Daughters have a 50% chance of being carriers like their mother but will have normal color vision since they would inherit a normal X chromosome from their father.
Are grasshoppers blind?
Grasshoppers are not blind. However, there vision is not spectacular, as their eyes are though to produce very grainy, blotchy images.
Color blindness is an X-linked recessive trait A color-blind man has a daughter with normal color vision She mates with a male who has normal color vision What is the expected phenotypic ratio of t?
The expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
What will happen if a normal woman married with color blind man?
If a normal woman (not a carrier of the color blindness gene) marries a color-blind man, their children will inherit their color vision traits based on the father's X-linked recessive gene for color blindness. Sons will have a 50% chance of being color blind, as they inherit the Y chromosome from their father and the X chromosome from their mother. Daughters will inherit one X chromosome from each parent, and since the mother has normal vision, they will be carriers of the color blindness gene but will not be color blind themselves. Therefore, all daughters will have normal color vision, while some sons may be color blind.
What is the typical range of eye vision for humans?
The typical range of eye vision for humans is between 20/20 and 20/200. 20/20 vision is considered normal, while 20/200 vision is considered legally blind.
What is the worst vision number you can have in your eyes?
The worst vision number you can have is 20/200. This means you can see at 20 feet what a person with normal vision can see at 200 feet. It is considered legally blind.
Is 20 200 bad vision?
20/200 means you can only see at 20 feet what a person with normal vision can see at 200 feet. Therefore you would be legally blind.
Is blindness a part of pink eye?
It's not normal to be blind unless your eye is swollen shut. But it's common to have blurred vision.
