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As far as I know, No. A negative order means a higher concentration of the reactant having a lower reaction rate. For example: concentration of A reaction rate ---- 4 M .1 M/s 1 M .4 M/s ---- rate1/rate2=k(A1)n/k(A2)n k canceled (.1M/s)/(.4M/s)=(4M/1M)n 1/4=4n n=-1 but the reaction rate is usually proportional to the concentration of the reactant, which means reactants with a higher concentration have a greater reaction rate, in a few case, increase the concentration of reactant have little effect for the reaction rate. So, the order of the reaction is usually positive in a few case, it's close to 0. For more information about the relationship between reaction rate and the concentration of recants check out: http:/en.wikipedia.org/wiki/Reaction_rate http:/www.chemguide.co.uk/physical/basicrates/concentration.html

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