Yes & No,
You are wanting the equation:
AB + C --> A + B + CA
Your equation is no longer balanced as you started with 1 A, and end with 2 A's.
Ok, let's try an example, and to try to make a balanced equation.
Water + ethene --> Hydrogen + Oxygen + ethane.
Now, I don't know if we could actually make the reaction work, but in theory it would be possible.
Let's now substitute in the symbols and try to balance the equation.
a(H2O) + b(C2H4) --> c(H2) + d(O2) + e(C2H6)
Ok, since we're conserving the carbons, let's set b=e=1
a(H2O) + C2H4 --> c(H2) + d(O2) + C2H6
In this case... if we let d=1, then a would have to equal 2, and we get:
2(H2O) + C2H4 --> H2 + O2 + C2H6
Count our Hydrogens, Carbons, and Oxygens:
4(H) + 2(O) + 2(C) + 4(H) --> 2(H) + 2(O) + 2(C) + 6(H)
and it all balances out.
Now, looking back at your original equation...
AB + C --> A + B + CA
Let A be Hydrogen Dimer (H2), or two hydrogen atoms,
B is Oxygen Dimer (O2), or two oxygen atoms,
C is Ethene. CA is Ethane (Ethene + 2 hydrogen atoms).
And you get:
A2B + C --> A + B + CA ... pretty close.
Again, this would probably require energy, and a little handwaving to make it all work, but one can get it to balance if one had initially started with 2 A atoms/molecules.
The balanced equation is Ca(OH)2 + H2SO4 → CaSO4 + 2H2O.
no , is the chemical formula by benda Benjamen
Calcium=Ca=Atomic number 20 9+11=20
If you mean Ca(OH)2(s) --> Ca2+(aq) + 2OH-(aq) this is the equation for the dissolving of calcium hydroxide in water.
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No. Here is a proof by counterexample that it does not.Given ab + bc + ca = 3:Assume toward a contradiction that abc is a cube. Then a = b = c.Without loss of generality, let a = 2, b = 2, and c = 2.Then ab = 4, bc = 4, and ca = 4.ab + bc + ca = 4 + 4 + 4 = 12.Therefore, 12 = 3, which is false, and so the original statement is false.
Given that ab = ba and bc = cb We can arrive at abbc = cbba by adding equal quantities to both sides of the equation By the cancellation law you're allowed to drop the bb from both sides of the equation to end up with ac = ca
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The aba-ca-by =2
2Ca + 3O2 + 2C -> 2CaCO3
It is already balanced
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
I think the answer is yes, but I cannot be sure. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals".
Ca + Br2 = CaBr2 doesn't need to be balanced.
The balanced equation is Ca(OH)2 + H2SO4 → CaSO4 + 2H2O.
Calcium and water react to form calcium hydroxide and hydrogen. Ca + 2H2O --> Ca(OH)2 + H2
a^2 + b^2 + c^2 - ab - bc - ca = 0=> 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ca = 0 => a^2 - 2ab + b^2 + b^2 - 2bc + c^2 + c^2 - 2ca + a^2 = 0 => (a - b)^2 + (b - c)^2 + (c - a)^2 = 0 Each term on the left hand side is a square and so it is non-negative. Since their sum is zero, each term must be zero. Therefore: a - b = 0 => a = b b - c = 0 => b = c.