In the reaction between CuSO4 and Mg, magnesium (Mg) is oxidized while copper (Cu) is reduced. Magnesium loses electrons to form Mg²⁺ ions, indicating oxidation, while copper ions (Cu²⁺) gain electrons to form elemental copper, indicating reduction. Thus, Mg is the reducing agent and Cu²⁺ is the oxidizing agent in this reaction.
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
CuSO4 isn't an element.
In the reaction between potassium permanganate (KMnO4) and hydrogen peroxide (H2O2), manganese in KMnO4 is reduced from +7 to +2 in the form of MnO2. The hydrogen peroxide is oxidized to water (H2O), where the oxygen in H2O2 goes from -1 to -2.
The net ionic equation for this process is: Ni(s) + Cu(+2)(aq) --> Ni(+2)(aq) + Cu(s). This is an oxidation-reduction reaction, where nickel is oxidized and copper is reduced.
CuSO4 · 5H2O has 5 water molecules attached to each CuSO4 molecule.
In this reaction, zinc (Zn) is oxidized to form zinc sulfate (ZnSO4) while copper (Cu2+) in copper sulfate (CuSO4) is reduced to copper (Cu). The zinc loses electrons (oxidized) to form zinc sulfate, while the copper gains electrons (reduced) to form solid copper.
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
Copper sulfur oxygen
To balance the equation CuSO4 + Na, follow these steps: Write down the unbalanced equation: CuSO4 + Na → ? Determine the products of the reaction based on the elements involved: CuSO4 + Na → Cu + Na2SO4 Now, balance the equation by ensuring that the number of atoms for each element is the same on both sides: CuSO4 + 2Na → Cu + Na2SO4
CuSO4 isn't an element.
In the reaction between potassium permanganate (KMnO4) and hydrogen peroxide (H2O2), manganese in KMnO4 is reduced from +7 to +2 in the form of MnO2. The hydrogen peroxide is oxidized to water (H2O), where the oxygen in H2O2 goes from -1 to -2.
In the presence of Biuret reagent, CuSO4 and KI can undergo a redox reaction where the Cu(II) ions from CuSO4 are reduced to Cu(I) while the iodide ions from KI are oxidized to iodine. This reaction forms a purple complex due to the interaction of Cu(I) ions with the peptide bonds in protein molecules.
They fit the pattern: element + compound --> different element + different compound. Example: Zn + CuSO4 --> Cu + ZnSO4.
A more reactive element displace the less reactive element from a compound.Example: Fe + CuSO4 = Cu + FeSO4
Fe+CuSO4^Cu+FeSO4
The balanced chemical equation for the reaction between H2S (hydrogen sulfide) and CuSO4 (copper(II) sulfate) is: H2S + CuSO4 → CuS + H2SO4 This equation is balanced as it shows the conservation of atoms of each element on both sides of the reaction.
No, CuSO4 is not an example of a chemical element. It is the chemical formula for copper sulfate, which is a compound made up of the elements copper, sulfur, and oxygen. Copper (Cu) is the element in this compound.