no. Since they are identical, their phenotype, or physical appearance, would be identical as well. hope that helps :)
The blending of the phenotype of the parents in the offspring is known as incomplete. colors of flowers can show incomplete dominance if a red flower is crossed with a white flower and their offspring are pink.
In a testcross, an individual with a dominant phenotype but unknown genotype is crossed with an individual that is homozygous recessive for the same trait. This helps determine the unknown genotype of the dominant individual based on the phenotypic ratios of the offspring. If any offspring display the recessive phenotype, it indicates that the dominant parent is heterozygous. Conversely, if all offspring show the dominant phenotype, the dominant parent is likely homozygous.
When a homozygous dominant female (genotype AA) is crossed with a homozygous recessive male (genotype aa), all offspring will inherit one dominant allele from the mother and one recessive allele from the father, resulting in a genotype of Aa for all offspring. The phenotype ratio will show all offspring displaying the dominant trait. Thus, the genotype ratio is 100% Aa, and the phenotype ratio is 100% expressing the dominant trait.
In sexual reproduction, there are tow parents so there is a mixture in genes. In asexual reproduction, there is one parent so looks identical to that parent
It would be exactly the same way you make any punnet square. Just remember that the Y chromosome on males is recessive to the X chromosome. So for example, if a certain recessive phenotype is carried on the X chromosome, and the offspring is a male, the male will show that phenotype (because Y is recessive to X). However if it is a female, she will not show the phenotype because we said it is a recessive X linked phenotype.
They always do.
The blending of the phenotype of the parents in the offspring is known as incomplete. colors of flowers can show incomplete dominance if a red flower is crossed with a white flower and their offspring are pink.
A gene that shows maternal effect inheritance is one where the phenotype of the offspring is determined by the genotype of the mother, rather than the offspring's own genotype. This means that even if the offspring carries a certain genetic variant, it will only display the phenotype associated with the mother's genotype.
If 50% of the offspring show the dominant phenotype and 50% show the recessive phenotype, it is likely that one parent is heterozygous (Aa) for the trait and the other parent is homozygous recessive (aa). This would result in a 1:1 ratio of offspring showing each phenotype.
In a testcross, an individual with a dominant phenotype but unknown genotype is crossed with an individual that is homozygous recessive for the same trait. This helps determine the unknown genotype of the dominant individual based on the phenotypic ratios of the offspring. If any offspring display the recessive phenotype, it indicates that the dominant parent is heterozygous. Conversely, if all offspring show the dominant phenotype, the dominant parent is likely homozygous.
No, the offspring of identical parents would not always look like the parents because everyone has dominant and recessive traits, where the recessive traits do not show but is still in DNA. That said, recessive traits not shown in parents can be passed on as dominant traits to offspring - making offspring not always identical to its parents. (this is also called genetic variation)
When a homozygous dominant female (genotype AA) is crossed with a homozygous recessive male (genotype aa), all offspring will inherit one dominant allele from the mother and one recessive allele from the father, resulting in a genotype of Aa for all offspring. The phenotype ratio will show all offspring displaying the dominant trait. Thus, the genotype ratio is 100% Aa, and the phenotype ratio is 100% expressing the dominant trait.
Recessive allele is a trait that doesn't show in one's phenotype (observable trait) if there is a dominant allelle present. Only when you inherit a recessive allele from both parents (aa for example and not Aa) does the trait show in your phenotype.
A trait that exhibits incomplete dominance, is one in which the heterozygous offspring will have a phenotype that is a blend between the two parent organisms. An example of this is when a homozygous red sweet pea flower crossed with a homozygous white sweet pea flower, their offspring will be heterozygous and have the pink phenotype, rather than either red or white.
A gerbil with a recessive gene would generally not show it, aka it will not show as a phenotype. However, there are slight differences in some gerbils with recessives, such as a lighter coat if the gerbil has a recessive c(h), g, or a.
They differed both in genotype and phenotype. Mendel's F1 generation were all heterozygous Tall. Where his F2 generation had genotype frequencies as follows: 1TT:2Tt:1tt and the phenotype frequency 3tall:1short This is assuming you are referring to his experiments using height as the factor. His other experiments had similar results just replace all the uppercase T's with the dominant allele and the lowercase t's with the recessive trait.
You would expect 1 homozygous dominant, 2 heterozygous dominant and 1 homozygous recessive offspring. This is because each parent has one dominant and one recessive allele. Therefore there is a 75% chance of a dominant phenotype and a 25% chance of a recessive phenotype.