No, calcium chloride will dissolve in water.
NaCl + CaF2 Check solubility rules to see if it even forms a precipate
The chemical reaction is:CaCl2 + 2 AgNO3 = 2 AgCl(s) + Ca(NO3)2The precipitate is silver chloride.
CaCl2(aq) + Pb(NO3)2(aq) ===> Ca(NO3)2(aq) + PbCl2(s) so a precipitate of PbCl2 (lead chloride) will form. The fact that equal volumes of 0.2 M are mixed indicates that all of the Pb^2+ and all of the Cl^- will precipitate out of solution leaving only Ca^2+ and NO3^- left in solution.
The reaction is:2 NaHCO3 + CaCl2 = CaCO3(s) + 2 NaCl + CO2 + H2O
No, because calcium is a less reactive metal than sodium, therefore the calcium will not replace/displace the sodium from the sodium hydroxide. There will be no reaction.
NaCl + CaF2 Check solubility rules to see if it even forms a precipate
The chemical reaction is:CaCl2 + 2 AgNO3 = 2 AgCl(s) + Ca(NO3)2The precipitate is silver chloride.
Precipitate because you're making a solid out of two liquids.
Ok, lets begin by writing out the reaction : 2AgNO3 +CaCl2 --> 2AgCl(s) + Ca(NO3)2 Precipitate = AgCl Now find the mol of compound in each solution: 14g AgNO3 x (mol/170g) = .082mol 4.83g CaCl2 x (mol/111g) = .044mol Determine limiting reactant: Notice in reaction that 2 CaCl2 molecules react with 1 AgNO3. Because 2(.044mol) > 1(.082mol), AgNO3 is your limiting reactant. Now that you know this you can find the mass of the precipitate .082molAgNO3x (2molAgCl/2molAgNO3)x(143.3g/molAgCl) = 11.75g b) Assuming all the AgNO3 is exhausted, there will be 2(.044)-(.082) = .006mol CaCl2 left .006mol x (111g/mol) = 0.67g CaCl2
(Don't forget to balance it) The precipitate here has to be 2NaCl, as Ca(CO3)2 technically dissolves.
When CaCl2 and Na2SO4 are mixed, the precipitate formed is CaSO4 (calcium sulfate). This is because Ca2+ ions from CaCl2 react with SO42- ions from Na2SO4 to form an insoluble salt, which precipitates out of the solution.
CaCl2(aq) + Pb(NO3)2(aq) ===> Ca(NO3)2(aq) + PbCl2(s) so a precipitate of PbCl2 (lead chloride) will form. The fact that equal volumes of 0.2 M are mixed indicates that all of the Pb^2+ and all of the Cl^- will precipitate out of solution leaving only Ca^2+ and NO3^- left in solution.
CaCl2 (solubility 745g/l) NaOH (solubility 1090g/l) CaCl2 + 2NaOH > Ca(OH)2 + 2NaCl (Double displacement reaction) Ca(OH)2 (Solubility 1.7g/l) NaCl/Table salt (Solubility 359g/l) I'm assuming that you'll be left with Calcium Hydroxide as a precipitate because it's not soluble whereas all other chemicals involved are soluble you should get a White precipitate of Calcium precipitate (Hydroxides aren't very soluble generally unless paired with an alkali metal)
When Na2CO3 and CaCl2 are mixed, a double displacement reaction occurs. The sodium ions from Na2CO3 switch places with the calcium ions from CaCl2 to form two new compounds: CaCO3 (calcium carbonate) and 2NaCl (sodium chloride). This reaction is also known as a precipitation reaction, as calcium carbonate is insoluble in water and will form a solid precipitate.
The reaction is:2 NaHCO3 + CaCl2 = CaCO3(s) + 2 NaCl + CO2 + H2O
Yes, Ca(OH)2 will precipitate from solution because at a pH of 8.0, the solution is basic enough to cause Ca(OH)2 to form. This is because Ca(OH)2 is more soluble in basic solutions due to the shift in equilibrium towards the formation of the hydroxide ions.
The net ionic equation for the reaction between Na2SO4 and CaCl2 is: Ca2+ + SO4^2- → CaSO4 This reaction involves the formation of calcium sulfate (CaSO4) precipitate.