Hydrogen and helium have different valence electron configurations. Hydrogen has one valence electron, and helium has two valence electrons. However, hydrogen does typically form covalent bonds in which it shares an electron, and thereby gains an effective electron configuration of two, like helium. Hydrogen also can form the H+ ion which has no electrons.
H- has one additional electron compared to H. The electronic configuration is: 1s2
Hydrogen (H) only has one electron. If you are talking about valence electrons, all of the elements in group 1A on the periodic table have one valence electron (H, Li, Na, K, Rb, Cs and Fr).
Hydrogen has one valence electron while carbon has 4. Since this is a covalent bond, a molecule is formed so all you need do is draw a C for carbon with 4 dashes forming an... 'x' around the carbon. At the end of each carbon write a H for hydrogen ....H ....| H-C-H ....| ....H Something like that but all dashes the same length and ignoring the periods..
The element with 1 electron in period 1 would be hydrogen.
In forming the molecule HF, the fluorine (F) atom attains the electron configuration of a stable octet by sharing one electron with hydrogen (H) to form a single covalent bond. This results in fluorine having a full outer shell with a total of eight electrons, achieving a stable electron configuration.
Se and Te will have the same valence-shell electron configuration as they are both in the same group (group 16) and have 6 valence electrons. Sr and Cs will have different valence-shell electron configurations as Sr is in group 2 with 2 valence electrons and Cs is in group 1 with 1 valence electron. N and O will have different valence-shell electron configurations as N has 5 valence electrons while O has 6. H and He will have different valence-shell electron configurations as H has 1 valence electron and He has 2.
Valence electron configuration in group 1A: ns1 in which n=1, 2, 3, 4, 5, ... etc. Starting with Hydrogen, H, electron configuration: 1s1 followed by Lithium, Li, electron configuration: (1s2), 2s1 (non valence electrons in () brackets)
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.
there is one valence electron in hydrogen, and it needs one more electron to become stable
H- has one additional electron compared to H. The electronic configuration is: 1s2
It is simple: 1s^1 Note: The "^" symbol means the the following number is in the form of a superscript.
K-O-H the potassium and hydrogen are in the first group of the periodic table of elements and therefor only need one set of electrons. oxygen is in the 6th, and therefor has 6 valence electrons. The oxygen also has 2 pairs of unshared electrons. K-O-H , oxygen has 2 pairs of unshared electrons.
No, hydrogen (H) has one electron in its outermost level.
Hydrogen (H) is in group 1 of the periodic table and has one valence electron. It typically forms one covalent bond by sharing its electron with another element to achieve a stable electron configuration.
1s1...it is simply an isotope so the number of neutrons changes but the number of electrons remains the same
Hydrogen (H) only has one electron. If you are talking about valence electrons, all of the elements in group 1A on the periodic table have one valence electron (H, Li, Na, K, Rb, Cs and Fr).
Group 1a in periodic table contains hydrogen and the alkali metals. the question does not specify which three out of the seven elements in the group are being referred to. The metals all ionise to form M+ ions e.g. Li+, Na+, K+ etc. Hydrogen is the odd one out- whilst it does lose an electron to form H+ (a bare nucleus with a charge of +1) it can also gain an electron (to achieve the noble gas configuration of He, helium) forming the H- hydride ion.