Yes, helium, like the other noble gasses, is most stable in the form of individual atoms.
An alpha particle is identical to B, a helium nucleus. Specifically, it consists of two protons and two neutrons, making it the same as the nucleus of a helium-4 atom.
the force of attraction b/w the nucleons is because of the continues transfer of newtons to protons and protons to newtons. If there are no newtons then only protons will be there in the nucleus. hence only repulsive force will b there making the nucleus unstable hence the atom will not exist in that situation...........
Option 'a' is correct.
No it does not. :o <===B
B stands for Boron. Boron ion (B³±) is cation but it is well known as non - metal. But if Only B is asked then as B is atom and atom is neutral in charge.
An alpha particle is identical to B, a helium nucleus. Specifically, it consists of two protons and two neutrons, making it the same as the nucleus of a helium-4 atom.
B- particles are electrons. They are not Helium nuclei.
The Nitrogen atom has 5 valence electrons and with three bonded e's it has one lone pair (2 left over ) which it donates to the Boron atom to coordinately bond with B to form F2HNBF3. The boron atom is also partially positive due to the more electronegative flourine atoms
D- Helium
An ionic bond will form between atom a and atom b if atom a loses electrons and atom b gains these electrons. Atom a becomes a positively charged ion (cation) and atom b becomes a negatively charged ion (anion), resulting in an electrostatic attraction between the two oppositely charged ions.
Multiply the numerator by itself, and then the denominator by itself. (a/b)^2 = (a ×a)/(b × b)
I. B. Whittingham has written: 'S-matrix for broadening of helium spectral lines by helium perturbers' -- subject(s): Helium, Perturbation (Quantum dynamics), S-matrix theory, Spectra, Spectral line broadening
B for what? I only remembered the atom bomb test called "Trintity" or sort of.
helium and hydrogen
yes any number by itself is a monomial like 5 or 2700. It can also be a variable like m or b.
The symbol for boron is B, and a neutral atom of boron has 5 electrons.
the force of attraction b/w the nucleons is because of the continues transfer of newtons to protons and protons to newtons. If there are no newtons then only protons will be there in the nucleus. hence only repulsive force will b there making the nucleus unstable hence the atom will not exist in that situation...........