Yes, helium, like the other noble gasses, is most stable in the form of individual atoms.
Option 'a' is correct.
No it does not. :o <===B
the force of attraction b/w the nucleons is because of the continues transfer of newtons to protons and protons to newtons. If there are no newtons then only protons will be there in the nucleus. hence only repulsive force will b there making the nucleus unstable hence the atom will not exist in that situation...........
B stands for Boron. Boron ion (B³±) is cation but it is well known as non - metal. But if Only B is asked then as B is atom and atom is neutral in charge.
Vitamin B itself is not an antioxidant, but some B vitamins like vitamin B2 (riboflavin) and vitamin B3 (niacin) have antioxidant properties by helping to combat oxidative stress in the body.
B- particles are electrons. They are not Helium nuclei.
D- Helium
Oh, dude, it's like when N and B see each other at a chemistry party and they're like, "Hey, wanna bond?" So, the N atom in NHF2 and the B atom in BF3 form a covalent bond by sharing a pair of electrons. It's like a chemical handshake, but with electrons instead of hands. So, yeah, they bond by sharing electrons, you know, just chemistry stuff.
An ionic bond will form between atom a and atom b if atom a loses electrons and atom b gains these electrons. Atom a becomes a positively charged ion (cation) and atom b becomes a negatively charged ion (anion), resulting in an electrostatic attraction between the two oppositely charged ions.
Multiply the numerator by itself, and then the denominator by itself. (a/b)^2 = (a ×a)/(b × b)
I. B. Whittingham has written: 'S-matrix for broadening of helium spectral lines by helium perturbers' -- subject(s): Helium, Perturbation (Quantum dynamics), S-matrix theory, Spectra, Spectral line broadening
B for what? I only remembered the atom bomb test called "Trintity" or sort of.
helium and hydrogen
yes any number by itself is a monomial like 5 or 2700. It can also be a variable like m or b.
The symbol for boron is B, and a neutral atom of boron has 5 electrons.
The electron configurations provided represent the electron arrangement in the outermost energy level of the atoms. Atom A has a 3s1 electron configuration, indicating it is in the third energy level with one electron in the s orbital. Atom B, on the other hand, has a 5s1 electron configuration, indicating it is in the fifth energy level with one electron in the s orbital. Therefore, the main difference between atom A and atom B is the energy level in which their outermost electrons reside.
Option 'a' is correct.