That is false
Transition metals have a complex arrangement of electrons.
Transition elements have unpaired electrons due to their partially filled d orbitals. These unpaired electrons can align their magnetic moments in the presence of an external magnetic field, making transition elements paramagnetic. The presence of unpaired electrons gives rise to magnetic properties in transition elements.
If you are filling in the electrons it will be in the 4d orbital. If you are removing electrons the first to come out is in the 5s electrons since transition metals lose 's' electrons before 'd' electrons
In general, when the transition metals lose electrons, the s shell electrons are lost before the d shell electrons. This is because the s electrons are higher in energy when the atom is in its ionized state. For example, in elements like iron (Fe), the 4s electrons are lost first, followed by the 3d electrons. This trend is observed across the periodic table, particularly in transition metals.
The second to last shell would be n=6, and the last transition element in n=6 would be mercury, (Hg), and it has 80 electrons, so that seems like it would be the correct answer. If you meant "in their second to last orbit", then the answer would be different.
Transition metals have a complex arrangement of electrons.
2 valence electrons are in iridium because iridium is a transition metal. Most transitions metal would have 2 valence electrons because the group before the transition metals are the alkaline-earth metals which contains 2 valence electrons in that group making the transition metals have 2 valence electrons.
How many valence electrons do transition elements have?
Transition elements have unpaired electrons due to their partially filled d orbitals. These unpaired electrons can align their magnetic moments in the presence of an external magnetic field, making transition elements paramagnetic. The presence of unpaired electrons gives rise to magnetic properties in transition elements.
Transition elements can lose electrons from their d sublevel when they react chemically. This is because the d sublevel contains the valence electrons involved in bonding for transition elements.
If you are filling in the electrons it will be in the 4d orbital. If you are removing electrons the first to come out is in the 5s electrons since transition metals lose 's' electrons before 'd' electrons
Zinc
Copper (Cu) has 2 valence electrons. It is located in the middle group of elements, called Transition Metals, and all transition metals have 2 valence electrons...hope that helped! =D
In general, when the transition metals lose electrons, the s shell electrons are lost before the d shell electrons. This is because the s electrons are higher in energy when the atom is in its ionized state. For example, in elements like iron (Fe), the 4s electrons are lost first, followed by the 3d electrons. This trend is observed across the periodic table, particularly in transition metals.
Noble gases have a full valence shell with 8 electrons, while all other groups typically have fewer valence electrons. Transition metals have varying numbers of valence electrons depending on their position in the periodic table.
Transition metals typically lose 1 to 4 electrons to achieve a stable electron configuration. The number of electrons lost depends on the specific transition metal and its position in the periodic table.
The second to last shell would be n=6, and the last transition element in n=6 would be mercury, (Hg), and it has 80 electrons, so that seems like it would be the correct answer. If you meant "in their second to last orbit", then the answer would be different.