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Is it true that people who are heterozygous recessive allele but who have a normal phenotype eill not pass the harmful recessive allele to their kids?
It depends on the genotype of the childs other parent. If your partner is heterozygous as well then there is a 25% chance your child will be homozygous recessive. If they are homozygous dominant then none of your children will have the phenotype of the recessive trait. They will just possibly be carriers of the recessive allele.
Why heterozygous for phenylketonuria appear normal at birth?
Individuals who are heterozygous for phenylketonuria (PKU) carry one normal allele and one mutated allele for the PAH gene, which leads to the production of the enzyme phenylalanine hydroxylase. Since the normal allele produces enough functional enzyme to metabolize phenylalanine effectively, heterozygous individuals usually do not exhibit symptoms of PKU at birth. Consequently, they appear normal because the enzyme activity is sufficient to prevent the toxic buildup of phenylalanine that characterizes the disorder in homozygous individuals.
If a man is heterozygous for the alleles that cause the condition and has children with a woman who lacks that defective allele?
If a man is heterozygous for the alleles that cause the condition and has children with a woman who lacks that defective allele, there is a 50% chance that each of their children will inherit the defective allele. This is because the man can pass on either the normal or defective allele, resulting in a 50% chance of passing on the defective allele.
The genetic disorder sickle cell disease is an example of heterozygous dominance?
Sickle cell disease is an example of codominance, not heterozygous dominance. In individuals who are heterozygous for the sickle cell allele, they exhibit a milder form of the disease called sickle cell trait, which demonstrates codominance of the normal and mutant hemoglobin alleles.
In certain breeds of dogs deafness is due to a recessive allele (d) of a particular gene and normal hearing is due to its dominant allele (D). What percentage of the offspring of a normal heterozygous?
If a normal heterozygous dog (Dd) is crossed with another normal heterozygous dog (Dd), the Punnett square shows the possible genotypes of the offspring: DD, Dd, Dd, and dd. This results in 25% DD, 50% Dd, and 25% dd. Therefore, 25% of the offspring would be expected to be deaf (dd).
Will a heterozygous female with hemophilia have blood that will clot normally?
Yes, because Hemophilia is recessive (if you have a normal allele, you won't have hemophilia, and heterozygous means that you have one normal and one abnormal allele).
Is it true that people who are heterozygous recessive allele but who have a normal phenotype eill not pass the harmful recessive allele to their kids?
It depends on the genotype of the childs other parent. If your partner is heterozygous as well then there is a 25% chance your child will be homozygous recessive. If they are homozygous dominant then none of your children will have the phenotype of the recessive trait. They will just possibly be carriers of the recessive allele.
Why heterozygous for phenylketonuria appear normal at birth?
Individuals who are heterozygous for phenylketonuria (PKU) carry one normal allele and one mutated allele for the PAH gene, which leads to the production of the enzyme phenylalanine hydroxylase. Since the normal allele produces enough functional enzyme to metabolize phenylalanine effectively, heterozygous individuals usually do not exhibit symptoms of PKU at birth. Consequently, they appear normal because the enzyme activity is sufficient to prevent the toxic buildup of phenylalanine that characterizes the disorder in homozygous individuals.
Can heterozygous for sickle cell have greater resistance?
Yes, individuals who are heterozygous for the sickle cell trait (having one normal hemoglobin allele and one sickle cell allele) can have greater resistance to malaria. The presence of the sickle cell allele provides some protection against the malaria parasite, as the altered shape of the red blood cells makes it less hospitable for the parasite to thrive. This selective advantage is particularly observed in regions where malaria is endemic, leading to a higher prevalence of the sickle cell trait in those populations.
Why is it not possible to get a colorblind female from a normal male and a heterozygous female?
Color blindness is typically inherited as an X-linked recessive trait. A colorblind female must have two copies of the colorblind allele (one from each parent), meaning she must inherit the allele from both her mother and father. In this scenario, the normal male (with a normal X chromosome) can only pass on a normal X chromosome to his daughters, while the heterozygous female has one normal X and one colorblind X, meaning she can pass on either allele. Therefore, the combination of a normal male and a heterozygous female cannot produce a colorblind daughter.
If a man is heterozygous for the alleles that cause the condition and has children with a woman who lacks that defective allele?
If a man is heterozygous for the alleles that cause the condition and has children with a woman who lacks that defective allele, there is a 50% chance that each of their children will inherit the defective allele. This is because the man can pass on either the normal or defective allele, resulting in a 50% chance of passing on the defective allele.
A healthy individual is a carrier of a lethal allele but is unaffected by it what is the probable genotype of this individual?
The probable genotype of this individual is likely heterozygous for the lethal allele, carrying one normal allele and one lethal allele. This individual is considered a carrier because they do not show any symptoms of the lethal allele's effects.
What is trans heterozygous?
Trans heterozygous is a diploid organism that is heterozygous but it has two different loci(genes). They each have one natural allele and allele that is different from the natural allele due to a mutation.
The genetic disorder sickle cell disease is an example of heterozygous dominance?
Sickle cell disease is an example of codominance, not heterozygous dominance. In individuals who are heterozygous for the sickle cell allele, they exhibit a milder form of the disease called sickle cell trait, which demonstrates codominance of the normal and mutant hemoglobin alleles.
In certain breeds of dogs deafness is due to a recessive allele (d) of a particular gene and normal hearing is due to its dominant allele (D). What percentage of the offspring of a normal heterozygous?
If a normal heterozygous dog (Dd) is crossed with another normal heterozygous dog (Dd), the Punnett square shows the possible genotypes of the offspring: DD, Dd, Dd, and dd. This results in 25% DD, 50% Dd, and 25% dd. Therefore, 25% of the offspring would be expected to be deaf (dd).
The allele for albinism is recessive to the allele for normal skin pigmentation what is the probability that a child of a heterozygous mother and albino father will be albino?
In this scenario, the mother is heterozygous for normal skin pigmentation (Aa) and the father is homozygous recessive for albinism (aa). The possible genotypes for their child are Aa (normal pigmentation) and aa (albino). Using a Punnett square, there is a 50% probability that the child will be albino (aa).
What is the best evidence to prove that Irene was heterozygous for hemophilia?
The best evidence to prove that Irene was heterozygous for hemophilia would be a genetic test showing the presence of one normal allele and one mutated allele of the gene responsible for hemophilia (F8 for hemophilia A or F9 for hemophilia B). Additionally, if Irene has a family history in which she has a son with hemophilia (who inherits the mutated allele) but does not express the condition herself, it would further support that she is a carrier (heterozygous) rather than homozygous.
