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How many grams of calcium are in 19050.9 g calcium chloride?
The gram atomic mass of calcium is 40.08, the formula of anhydrous calcium chloride is CaCl2, showing that each formula unit contains one calcium atom, and the gram formula mass of anhydrous calcium chloride is 110.99. Therefore, 19050.9 grams of calcium chloride contains 19050.9(40.08/110.99) or 6.880 X 103 grams, to the justified* number of significant digits. ____________________________________________ *There may well be tables of gram atomic and gram formula masses more modern than the one I am using that would allow for more significant digits in the answer.
How many grams do you need to add to prepare a 2M solution if you have 2L solution?
4 gram molecular weights (moles): However many grams four moles* of the solute is. * Hint: four moles of sodium chloride weighs less than four moles of sucrose.
How many grams of lead 2 chloride can be produced from 14.6 liters of chlorine gas at STP and 285 milliliters of 0.250 molarity lead 2 nitrate?
The formula unit for lead (II) chloride is Pb(NO3)2. This formula shows that each formula unit contain one lead (II) ion. By the definition of molarity, a liter of a 0.250 molar solution of lead (II) nitrate therefore contains 0.25 gram formula units of lead (II) ions per liter of solution, so that 250 milliliters of such a solution will contain 250/1000 of this amount, or 0.0625 gram formula units. Assuming that chlorine is an ideal gas, 22.4 liters of it at STP contain one mole. Since gases are homogeneous, 14.6 liters of it will contain 14.6/22.4 or 0.652 moles. The formula of gaseous chlorine at STP is Cl2. Therefore, 0.652 moles of it contain twice this number of chlorine atoms, or 1.305 "moles" of such atoms. The formula unit for lead (II) chloride is PbCl2. Therefore, each gram formula unit of lead (II) requires two gram formula units of chloride ions. Comparison shows that there is a large excess of chlorine over that required to form lead (II) chloride from the 0.0625 gram formula units of lead (II) contained in the specified amount of solution. Lead (II) is therefore the limiting reagent in this combination, and 0.0625 gram formula units of PbCl2 can be produced. The gram atomic mass of lead is 207.2 and that of chlorine is 35.453. Therefore, the mass of lead (II) chloride that can be produced is 0.0625[207.2 + 2(35.453)] or 17.4 grams, to the justified number of significant digits.
How many grams calcium are in 100 grams calcium chloride?
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
How many grams in 1 percent solution?
A 1% solution normally contains 1 gram of active ingredient per 100 ml of solution (weight-volume percent) Could also be 1gm per 100 gms (weight-weight percent)- but normally weight-volume is used.
What gram of sodium chloride is required to make 500ppm of sodium chloride?
It depends on the volume, if we consider 1 liter of the solution 500 mg of sodium chloride is needed.
When 1 gram of zinc chloride ZnCl2 is dissolved in water the heat evolved is 0.53kJ Calculate the molar heat of substance of solution of zinc chloride?
To calculate the molar heat of solution of zinc chloride, we use the heat evolved by dissolving 1 gram of ZnCl2 in water. First, we convert the mass of ZnCl2 to moles using its molar mass of 136.3 g/mol. Then, we divide the heat evolved by the number of moles dissolved to get the molar heat of solution. In this case, the molar heat of solution would be 3.89 kJ/mol.
How to prepare 1000 ppm chloride solution from sodium chloride?
To prepare a 1000 ppm chloride solution from sodium chloride, first calculate the mass of sodium chloride needed using the formula: (ppm concentration * volume of solution in liters) / 1000. Then dissolve this calculated mass of sodium chloride in the desired volume of water to make the solution. Finally, ensure the solution is thoroughly mixed before testing the concentration with appropriate methods.
How many 2 mg tablets is in a gram?
If by mg u mean milligram then there are 500 tablets in a gram
How many meq in one gram chloride?
One gram of chloride is equal to 1 milliequivalent (mEq).
How many 5mg tablets to make 1 gram?
200. there are 1000mg in a g
How many 0.25 gram tablets will you give to equal 1000 mg ampicillin?
1000 mg is a gram. It would take four 0.25 g tablets to equal one gram. So it would take four 0.25 g tablets to equal 1000 mg.
1 gram of medication. the container label reads 250 mg. how many tablets?
I think there is 1000mg in a gram, so that would be four tablets if they are 250mg each.
How many tablets would you need if a doctor ordered 500 mg of Carafate tablets and you have 1 gram tablets available how many tablets will you give?
1/2
How do you make 1000 ppm solution of chloride ion?
Dear friends, PPM means Part Per Millions, So It means if you takes 1 gm of Solid Chloride Ions and Dissolve it in D. water. The Current Stock solution is having 1000 PPM of Chloride Ions. NOW if you want lesser PPM solution from this stock Solution, follows below rule- Required PPM Solution (A) ---------------------------------- X Required Volume of A PPM solution === Nos. of mL Stock Solution PPM (1000) to be taken from this stock solution and add in required Volume. Dr.P.Khemariya Research Scientist R&D dr.p.khemariya@gmail.com
How do you prepare 0.2N Sodium chloride solution?
NaCl is the formula for Sodium Chloride, from that you can work out the gram formula mass. RAM Na = 23 RAM Cl = 35.5 gfm (NaCl) = 58.5g mol-1 assuming that you need 0.1l of NaCl m = 58.5*0.1 = 5.85g So dissolve 5.85g in water for a 0.2 mole solution
How many grams of calcium are in 19050.9 g calcium chloride?
The gram atomic mass of calcium is 40.08, the formula of anhydrous calcium chloride is CaCl2, showing that each formula unit contains one calcium atom, and the gram formula mass of anhydrous calcium chloride is 110.99. Therefore, 19050.9 grams of calcium chloride contains 19050.9(40.08/110.99) or 6.880 X 103 grams, to the justified* number of significant digits. ____________________________________________ *There may well be tables of gram atomic and gram formula masses more modern than the one I am using that would allow for more significant digits in the answer.
