2 Al + Fe2O3 ----> Al2O3 + 2 Fe
No, Fe2O3 is ionic
It is impossible to balance AL CI H2 because it is an incomplete equation. There are products missing from this chemical equation. If your query was how do you balance 2 HCI + 2AL then the answer would be 2 HC1 + 2 AL = 2 ALCI + H2.
Because the Aluminium is a more reactive metal then the Iron.
Fe2O3 (diiron trioxide) is a chemical compound not am element.
The balanced chemical equation for the formation of iron(III) oxide (Fe2O3) from iron (Fe) and oxygen (O2) is: 4 Fe + 3 O2 → 2 Fe2O3. From the equation, it can be seen that 3 moles of O2 are required to produce 2 moles of Fe2O3. Therefore, to produce 107.9 moles of Fe2O3, you would need (107.9 moles Fe2O3) × (3 moles O2 / 2 moles Fe2O3) = 161.85 moles of O2.
This equation is not balanced as given. To balance it, you need to change the coefficients of the reactants and products. The balanced equation is 4Al + 3O2 -> 2Al2O3.
The balanced chemical equation for the reaction between iron oxide (Fe2O3) and aluminum (Al) is 2Al + Fe2O3 → Al2O3 + 2Fe. This shows that 2 moles of Al react with 1 mole of Fe2O3. Therefore, 2.5 moles of Al would need 1.25 moles of Fe2O3 to completely react.
The balanced equation for the thermite reaction involving iron(III) oxide (Fe2O3) and aluminum (Al) is: Fe2O3 + 2Al -> 2Fe + Al2O3 From the equation, it is clear that 1 mole of Fe2O3 reacts with 2 moles of Al. The number of moles of Al needed to react with 6.258 moles of Fe2O3 is 3.129 moles (6.258 moles Fe2O3 * 2 moles Al / 1 mole Fe2O3). Since 8.359 moles of Al are provided, the excess amount of Al is 8.359 moles - 3.129 moles = 5.230 moles.
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
Fe2O3 + 2Al --> Al2O3 +2 Fe The reaction is commonly known as thermite for the enormous amount of heat produced. The iron produced by the reaction is molten.
The equation FeSO4 = Fe2O3 + SO2 + SO3 is not balanced. To balance it, one possible balanced equation could be: 2FeSO4 = Fe2O3 + 2SO2 + 2SO3.
Rust is formed from Fe2O3.nH2O and Fe(OH)3.
The balanced equation is 2Fe2O3 + 4Al ----> 2Al2O3 + 3Fe. The coefficient of Fe is 3.
81.93%
Because C and Fe appear in uncombined, atomic form in this equation we can ignore them initially and just look at the Fe2O3 and CO2. There are an odd number of atoms of O in the Fe2O3 and a odd number in the CO2. If I just double the number of molecules of Fe2O3 going into the reaction then this will also double the number of atoms of oxygen, thereby making the number even(which is what I want, eh). Here's what I have so far:2 Fe2O3 + C -> Fe + CO2Because there are six oxygen atoms on the left there must be six on the right. Therefore there are three CO2 molecules:2 Fe2O3 + C -> Fe + 3 CO2Finally:Four Fe's going in means four must come out.Three C's coming out means three must go in.2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
MgO + Fe ----> Fe2O3 + Mg (unbalanced)Balanced Answer: 3,2,1,3Tip: First look for the most abundant element in the most complex molecule in this unbalanced one: which in this case is O in 'Fe2O3'Then correct the number of O's at the other site: so filling in 3MgOThen correct the other elements: 2Fe and 3Mg accordingly.So having done this the reaction will be balanced by the coefficients:3MgO + 2Fe ----> Fe2O3 + 3Mg
3Fe + 4(H2O) ---> Fe3O4 + 4(H2) You really should learn this, its not that hard =D