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How many atoms of phosphorus are in 8.90 mol of copperII phosphate?
To find the number of phosphorus atoms in 8.90 mol of copper(II) phosphate (Cu₃(PO₄)₂), we first identify that each formula unit contains 2 phosphorus (P) atoms. Thus, in 8.90 mol of copper(II) phosphate, the total number of phosphorus atoms is calculated as follows: 8.90 mol × 2 P/mol = 17.8 mol of phosphorus atoms. To convert moles to atoms, we multiply by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol): 17.8 mol × (6.022 \times 10^{23}) atoms/mol ≈ (1.07 \times 10^{24}) phosphorus atoms.
How do you convert 0.25 moles gold to atoms?
1 mol = 6,022 140 857(79).10e23 atoms.0,25 mol is 1,50553521425.10e23 atoms.
How do you determine the number of atoms in CaCO3?
To determine the number of atoms in CaCO3, you would first calculate the molar mass of CaCO3 (40.08 g/mol + 12.01 g/mol + 3(16.00 g/mol)). Then, you would divide the given mass of CaCO3 by the molar mass to find the number of moles. Finally, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to the number of atoms in CaCO3.
Does 23 g of sodium and 238 g of uranium have equal number of atoms in them?
No, the number of atoms in a substance is determined by Avogadro's number (6.022 x 10^23 atoms/mol). To calculate the number of atoms, you need to convert the mass of each element to moles first using their respective molar masses, which are 22.99 g/mol for sodium and 238.03 g/mol for uranium.
Calculate the number of atom in 13.2 mol copper?
To calculate the number of atoms in 13.2 mol of copper, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Multiply 13.2 mol by Avogadro's number to get the number of atoms: 13.2 mol * (6.022 x 10^23 atoms/mol) = 7.93 x 10^24 atoms. Therefore, there are approximately 7.93 x 10^24 atoms in 13.2 mol of copper.
How do you calculate the number of atoms in 6980 of nitrogen?
To calculate the number of atoms in 6980 grams of nitrogen, you would first convert the mass of nitrogen to moles using the molar mass of nitrogen (~14 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Overall, the calculation would be 6980 grams of nitrogen * (1 mol / 14 grams) * (6.022 x 10^23 atoms / 1 mol).
How many atoms are in 0.0010 grams of calcium?
To calculate the number of atoms in 0.0010 grams of calcium, you would first convert the mass to moles using the molar mass of calcium. Then, you would use Avogadro's number to convert moles to atoms. The formula would be: (0.0010 g / 40.08 g/mol) * 6.022 x 10^23 atoms/mol.
How do you convert 5.1e21 atoms into moles?
1 mole equals an Avagadro number of particles = 6.022 x 1023 so5.1 x 1021 /6.022 x 1023 = 8.469 x 10-3
How many atoms of phosphorus are in 8.90 mol of copperII phosphate?
To find the number of phosphorus atoms in 8.90 mol of copper(II) phosphate (Cu₃(PO₄)₂), we first identify that each formula unit contains 2 phosphorus (P) atoms. Thus, in 8.90 mol of copper(II) phosphate, the total number of phosphorus atoms is calculated as follows: 8.90 mol × 2 P/mol = 17.8 mol of phosphorus atoms. To convert moles to atoms, we multiply by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol): 17.8 mol × (6.022 \times 10^{23}) atoms/mol ≈ (1.07 \times 10^{24}) phosphorus atoms.
How do I convert 5.73 1024 atoms of carbon to moles of carbon. Round your answer to three significant figures?
To convert atoms of carbon to moles, you need to divide the number of atoms by Avogadro's number, which is (6.022 \times 10^{23}) atoms/mol. Thus, the calculation is: (\frac{5.73 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} \approx 9.50 \text{ mol}) of carbon.
How many aluminum atoms are in 2.78g of aluminum?
To calculate the number of aluminum atoms in 2.78g of aluminum, you first need to convert the mass to moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to determine the number of atoms. The calculation would be: (2.78g Al) / (26.98 g/mol) * (6.022 x 10^23 atoms/mol).
How many atoms are present in 80.0 mol of zirconium?
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
How many atoms are in 179 g of calcium?
To find the number of atoms, first convert the mass of calcium (179 g) to moles using the molar mass of calcium (40.08 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of calcium to atoms. Calculate as follows: 179 g / 40.08 g/mol = 4.47 mol x 6.022 x 10^23 atoms/mol = approximately 2.69 x 10^24 atoms.
Calculate the number of atoms in 0.551 g of potassium K?
To calculate the number of atoms in 0.551 g of potassium (K), you first need to convert the mass to moles using the molar mass of potassium (39.10 g/mol). Next, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, 0.551 g of potassium would contain approximately 7.1 x 10^22 atoms.
How many phosphorus atoms does it take to equal 30.973 grams?
To determine the number of phosphorus atoms in 30.973 grams, you would first convert the mass to moles using the molar mass of phosphorus (30.973 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of phosphorus atoms, which would be 30.973 grams / 30.973 g/mol * 6.022 x 10^23 atoms/mol.
What relationships are needed to convert 1.5 grams of carbon to the number of carbon atoms?
To convert 1.5 grams of carbon to the number of carbon atoms, you would need to use Avogadro's number, which is the number of atoms in one mole of a substance (6.022 x 10^23 atoms/mol), and the molar mass of carbon (12.01 g/mol). By dividing the given mass of carbon (1.5 g) by the molar mass of carbon, you can convert the grams to moles, and then use Avogadro's number to calculate the number of carbon atoms.
How do you convert chlorine atoms to moles of chlorine atoms?
To convert the number of chloride atoms to mols of chlorine atoms, simply multiply by Avogadro's number. This number is 6.022E23. Note that chlorine typically exists as a diatomic molecule, consisting of two chlorine atoms.
