Without knowing the mass and the specific heat of the substance involved this cannot be calculated.
Specific heat capacity is the amount of heat energy required to raise the temperature of one unit mass of a substance by one degree Celsius.
Quantity of Energy= mass x temperature change x specific heat capacity For example: Find the amount of energy needed to raise the temperature of 0.20 kg of lead by 15 degree Celsius if the specific heat capacity of lead is 0.90 J/g degree Celsius. Answer: J=200g x 15 degree Celsius x 0.90 J/g degree Celsius = 2700 J
The three measurements of heat are temperature, specific heat capacity, and heat capacity. Temperature measures the average kinetic energy of particles in a substance, while specific heat capacity is the amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius. Heat capacity is the total amount of heat required to raise the temperature of a substance by one degree Celsius.
The quantity of heat required to raise the temperature of 1 gram of a substance by 1 degree Celsius is defined as the specific heat capacity of that substance. It is measured in joules per gram degree Celsius (J/g°C) or in calories per gram degree Celsius (cal/g°C).
539 calories per gram for heat of vaporization plus 1 cal/gram/degree C 100 degrees C - 80 degrees C = 20 degrees C (539 calories + 20 calories) X 50 kg X 1000 gm/kg = 27950000 cal = 27,950 kcal
The specific heat capacity of air is approximately 1.005 kilojoules per kilogram degree Celsius.
Assuming standard atmospheric pressure, 2260 kilojoules.
To melt 25g of ice at 0 degrees Celsius, you need 334 J/g of energy (latent heat of fusion of ice). To convert this to kilojoules: 334 J/g * 25g = 8350 J = 8.35 kJ.
question makes no sense.....
The specific heat of water is 4186 joules per kilogram degree Celsius.
Energy from food is measured in calories or kilocalories (or Calories with a capital "C"). On food labels, the Calorie (kilocalorie) form is used.A calorie is the amount of energy it takes to heat up one gram of water one degree Celsius. It is about 4.2 Joules.A Calorie (or kilocalorie) is the amount of energy it takes to heat up one kilogram of water one degree Celsius. It is about 4.2 KiloJoules.
The specific heat of engine oil can vary depending on the type and composition of the oil, but it is typically around 0.45 J/g°C. This means that it requires 0.45 joules of energy to raise the temperature of 1 gram of engine oil by 1 degree Celsius.
6.276 kJ
It would depend on the temperature of the water, or average kinetic energy. (KE) However, what you may be looking for is how much heat is needed to raise the KE, or temperature, of water. 4.184 kilojoules per gram is the heat required to raise the temperature of water 1 degree Celsius.
It boils
The specific heat of water is 1 calorie per gram per degree Celsius 1 cal/g/degree celsius
6.276 kJ