How do you draw BrF2 plus in Lewis dot structures?

Answer 1

It would look something like this

.. .. ..

: F ----Br -----F:

.. .. ..

There are 21 valence electrons in neutral BrF2, so there will be one unpaired. Draw each F having a shared pair, giving each F 8 electrons. The central Br atom will have 9 electrons.

If the charge is BrF2 there will only be 8 electrons around Br, if the charge is BrF2- then there will 10. BrF2+ is well known.

Answer 2

To draw the Lewis dot structure for BrF2, start by placing the least electronegative element (Br) in the center. Add the two fluorine (F) atoms around the bromine atom, each bonded by a single bond to Br. Finally, add lone pairs to the fluorine atoms to complete the octet rule for each atom. This will result in a structure where Br is surrounded by two F atoms, each with three lone pairs.