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It would look something like this

.. .. ..

: F ----Br -----F:

.. .. ..

There are 21 valence electrons in neutral BrF2, so there will be one unpaired. Draw each F having a shared pair, giving each F 8 electrons. The central Br atom will have 9 electrons.

If the charge is BrF2 there will only be 8 electrons around Br, if the charge is BrF2- then there will 10. BrF2+ is well known.

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Related Questions

How do you draw a Lewis structure for Be2 plus?

To draw a Lewis structure for Be2+, start by writing the symbol for beryllium. Since Be2+ has a 2+ charge, it has lost two electrons. Place the two electrons as individual dots around the beryllium symbol, as there is no other atom bonded to it. The Lewis structure for Be2+ is simply Be with two dots around it.


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