It would look something like this
.. .. ..
: F ----Br -----F:
.. .. ..
There are 21 valence electrons in neutral BrF2, so there will be one unpaired. Draw each F having a shared pair, giving each F 8 electrons. The central Br atom will have 9 electrons.
If the charge is BrF2 there will only be 8 electrons around Br, if the charge is BrF2- then there will 10. BrF2+ is well known.
To draw the Lewis dot structure for Al³⁺, start with the aluminum atom, which has three valence electrons. However, since Al³⁺ indicates that the aluminum has lost three electrons, it will have no dots around it in the Lewis structure. Therefore, the Lewis dot structure for Al³⁺ is simply represented as "Al³⁺" with no dots, indicating that there are no remaining valence electrons.
To draw a Lewis structure for Be2+, start by writing the symbol for beryllium. Since Be2+ has a 2+ charge, it has lost two electrons. Place the two electrons as individual dots around the beryllium symbol, as there is no other atom bonded to it. The Lewis structure for Be2+ is simply Be with two dots around it.
1 Source: My online chemistry book.
To describe the bonding in the cation PBr₄⁺, only one Lewis structure is necessary. In this structure, phosphorus (P) is the central atom surrounded by four bromine (Br) atoms, with a formal positive charge on the phosphorus due to the loss of one electron. This results in a tetrahedral geometry, and there are no resonance structures needed for PBr₄⁺, as the single Lewis structure adequately represents the bonding.
Mg2+
To draw the Lewis dot structure for Al³⁺, start with the aluminum atom, which has three valence electrons. However, since Al³⁺ indicates that the aluminum has lost three electrons, it will have no dots around it in the Lewis structure. Therefore, the Lewis dot structure for Al³⁺ is simply represented as "Al³⁺" with no dots, indicating that there are no remaining valence electrons.
To draw a Lewis structure for Be2+, start by writing the symbol for beryllium. Since Be2+ has a 2+ charge, it has lost two electrons. Place the two electrons as individual dots around the beryllium symbol, as there is no other atom bonded to it. The Lewis structure for Be2+ is simply Be with two dots around it.
Two equivalent Lewis structures are necessary to describe the bonding in NH4+ because nitrogen in the ammonium ion has a full octet and can form a single coordinate covalent bond with each of the four hydrogen atoms, resulting in two resonance structures.
1 Source: My online chemistry book.
To describe the bonding in the cation PBr₄⁺, only one Lewis structure is necessary. In this structure, phosphorus (P) is the central atom surrounded by four bromine (Br) atoms, with a formal positive charge on the phosphorus due to the loss of one electron. This results in a tetrahedral geometry, and there are no resonance structures needed for PBr₄⁺, as the single Lewis structure adequately represents the bonding.
Sorry, it's impossible to draw with a keyboard!
Download and install the WinBGIM Devpack. Once installed, you can include graphics.h to draw graphics.
Structures in C and C++ differ in that C structures do not have an automatic typdef associated with them.
2 dots
if while switch
Mg2+
I have a 1989 Browning Accelerator Plus and I was wanting to adjust the draw length?