The bond angle of SO4 (sulfate ion) is approximately 109.5 degrees. This is because sulfate has a tetrahedral molecular geometry, similar to methane (CH4), with four electron pairs surrounding the sulfur atom. Each of the four oxygen atoms forms a single bond with the sulfur atom, resulting in a symmetrical tetrahedral shape and bond angle.
The bond angle of BF2 is 120 degrees.
The question is nonsense. WHICH bond angle? There are many of them in a molecule the size of estradiol.
The value of the bond angle in XeF2 is 180 degrees.
90 degrees is the value of the smallest bond angle in IF4.
The bond length is equal to the linear distance between the nuclei of the bonding atoms. The bond angle is equal to the angle between any two consecutive bonds in a molecule or ion. Bond angles of molecules and ions are usually determined by using the VSEPR theory.
how to draw a blunt angle
To draw an adjacent angle you should draw an angle and inside that angle draw a semi-line. Make sure that both angles are not equal.
Draw an L and draw a line coming from the origin of the angle. That dividing line is an angle bisector.
Sulphur dioxide has 2 sigma bond electron pairs and 1 lone pair of electrons, meaning the shape is V-shaped, or bent. There is extra repulsion from the lone pair of electrons, so the bond angle is a little smaller than 120 degrees. - 119 degrees is the answer.
The bond angle of AlCl3 is 120 degrees.
The bond angle of N2O is 180 degrees.
The bond angle in CO2 is 180 degrees.
No, it is Ionic.
The bond angle for H2S is approximately 92 degrees.
MgSO4 contains both ionic and covalent bonds. The bond between Mg and SO4 is primarily ionic, with Mg2+ and SO4 2- ions attracting each other. However, within the SO4 ion, the bonds between S and O atoms are covalent.
draw the outside angle if you want to show 270 degrees then you draw a 90 degree angle but draw the circle outside of it
by draw it....:)