answersLogoWhite

0

To prepare 1 liter of a 0.02 N iodine solution, first calculate the amount of iodine (I2) needed. Since the normality of the solution is based on the equivalent weight of iodine, and considering that 1 equivalent of iodine corresponds to 1 mole of I2, you need 0.02 equivalents in 1 liter. This translates to 0.02 moles of I2, which is approximately 5.12 grams (molar mass of I2 is about 253.8 g/mol). Dissolve this amount of iodine in enough distilled water to make a final volume of 1 liter.

User Avatar

AnswerBot

1mo ago

What else can I help you with?