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How do you prepare sea water solution?

Dissolve 30-40 g of sodium chloride in 1 L of water.


How much water must be added to 425 g of formaldehyde to prepare a 40.0 percent by mass solution of formaldehyde?

To calculate the amount of water needed, first determine the mass of formaldehyde in the final solution. Since the solution is 40.0% formaldehyde by mass, the mass of formaldehyde is 40.0% of the final solution mass. Subtract the mass of formaldehyde in 425 g from this value to find the mass of water needed to prepare the solution.


How do you prepare 5mg percent working uric acid standard solution from stock uric acid standard solution?

Preparation of standards Prepare a stock uric acid solution of 100 mg/L. Dilute it to give working concentrations of 10, 20, 30, 40, 50 and 60 mg/L. Procedure:1 Prepare a 100 mg/L stock solution of uric acid Weigh out 100 mg uric acid, transfer it to a 1 L volumetric flash, add about 900 ml distilled water, and then add about 100 µl of 0.6 N NaOH to help dissolve the uric acid. Make up to the volume with water when uric acid is fully dissolved.2 Dilute the stock solution to give working concentrations of 10, 20, 30, 40, 50, 60 mg/L. To prepare 50 ml of the working standards 5, 10, 20, 30, 40, 50 mg/L respectively, weigh 10, 15, 20, 25, 30 g of stock solution into 50 ml volumetric flasks and make up to volume with distilled water.


What is urea N 40?

Usually it means a 40% solution of Urea.


How will prepare 200ml of 10 percent NaOH Solution?

Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...

Related Questions

What Calculate mass of potassium chloride required to prepare its 40 solution in 100g of water?

To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.


What amount of NaOH is required to prepare 1N NaOH solution and why only that amount is used?

To prepare a 1N NaOH solution, you would need to dissolve 40 grams of NaOH in water to make 1 liter of solution. This amount is used because 1N solution means 1 mole of NaOH per liter of solution, and the molar mass of NaOH is 40 g/mol, so 40 grams of NaOH is needed to have 1 mole in 1 liter of solution.


How do you prepare sea water solution?

Dissolve 30-40 g of sodium chloride in 1 L of water.


How do you prepare 40 percent of potassium sodium tartrate?

To prepare a 40% solution of potassium sodium tartrate, you would need to weigh out the appropriate amount of the salt and dissolve it in a specific volume of water to get the desired concentration. For example, to prepare 100mL of a 40% solution, you would mix 40g of potassium sodium tartrate with enough water to bring the final volume to 100mL.


How much water must be added to 425 g of formaldehyde to prepare a 40.0 percent by mass solution of formaldehyde?

To calculate the amount of water needed, first determine the mass of formaldehyde in the final solution. Since the solution is 40.0% formaldehyde by mass, the mass of formaldehyde is 40.0% of the final solution mass. Subtract the mass of formaldehyde in 425 g from this value to find the mass of water needed to prepare the solution.


What is 4N NaOH?

The atomic weight of Na-OH is 23+16+1= 40. So to prepare the one N solution of Na-OH, you need to add 40 grams of Na-OH in one litre of water. To prepare the 4N Na-OH solution, you need to add 160 grams of Na-OH in one litre of water.


How many 250 mcg lutein tablets to make 10 mg?

40 tablets of 250mcg each to equal 10mg


What is the solution to -x equals -40?

x = 40


What is 40 percent of 40 dollars?

Its $16 solution: $40*40/100 = $16


What is 40 milligrams in centigrams?

40mg is 4cg (@10mg per centigram).*Centigrams x 10 = mg*Milligrams/10 = cg


How many ml of 5 M are required to prepare 1000 ml of 0.02 M NaCl solution what is the dilution factor of this solution?

To prepare 1000 ml of 0.02 M NaCl solution, you would need 40 ml of 5 M NaCl solution, which you can calculate using the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired concentration, and V2 is the final volume. The dilution factor in this case would be 25, as you are diluting the 5 M solution 25 times to achieve the desired 0.02 M concentration.


How do you prepare 5mg percent working uric acid standard solution from stock uric acid standard solution?

Preparation of standards Prepare a stock uric acid solution of 100 mg/L. Dilute it to give working concentrations of 10, 20, 30, 40, 50 and 60 mg/L. Procedure:1 Prepare a 100 mg/L stock solution of uric acid Weigh out 100 mg uric acid, transfer it to a 1 L volumetric flash, add about 900 ml distilled water, and then add about 100 µl of 0.6 N NaOH to help dissolve the uric acid. Make up to the volume with water when uric acid is fully dissolved.2 Dilute the stock solution to give working concentrations of 10, 20, 30, 40, 50, 60 mg/L. To prepare 50 ml of the working standards 5, 10, 20, 30, 40, 50 mg/L respectively, weigh 10, 15, 20, 25, 30 g of stock solution into 50 ml volumetric flasks and make up to volume with distilled water.