Example: starting fom nitric acid 65 %
For 1 000 mL nitric acid solution 6 N:
- put in a clean conical volumetric flask of 1L, 581,6 mL of the 65 % acid
- add slowly demineralized water to the mark, at 20 0C
- attach the cap of the flask
- stir the flask
- attach a label with HNO3 6 N, the date of preparation, name of the operator
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
You get 300 mL of 0.0100 M Sr(NO3)2 solution
To prepare a chitosan solution, dissolve chitosan powder in an acidic solution (such as acetic acid or hydrochloric acid) with stirring. Adjust the pH as needed and filter the solution to remove any undissolved particles. The concentration of the chitosan solution can be adjusted by varying the amount of chitosan powder used.
The reaction is:Pb(NO3)2 + 2 HCl = PbCl2(s) + 2 HNO3
10
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
To prepare a 6N NaOH solution, you would need to dissolve 240 grams of sodium hydroxide (NaOH) pellets in enough distilled water to make 1 liter of solution. This will result in a 6N (Normal) solution of NaOH. Remember to handle NaOH with caution as it is a strong base and can cause burns.
To prepare a 6N solution of ammonium hydroxide, you would first need to calculate the molarity of the concentrated ammonium hydroxide solution you have on hand. Typically, concentrated ammonium hydroxide solutions are around 28-30% NH3 by weight. To make a 6N solution, you would dilute the concentrated solution with the appropriate amount of water to achieve a final concentration of 6N. It is crucial to handle concentrated ammonium hydroxide with care as it is a corrosive substance and can cause burns upon contact with skin or eyes.
To prepare 6N HCl from 1N HCl, you can dilute the 1N HCl by adding 6 times the volume of water to the 1N HCl solution. For example, mix 1 volume of 1N HCl with 6 volumes of water to get a final concentration of 6N HCl. Make sure to add acid to water slowly with stirring to avoid splashes and heat generation.
A 6N HCl solution refers to a solution of hydrochloric acid (HCl) where the concentration is 6 normal (6N). This means that the solution contains 6 moles of HCl per liter of solution. It is a common reagent used in laboratory settings for various chemical reactions and analyses.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
To prepare 0.500 L of 0.470 M HNO3 solution, you would need 103.6 mL of the 11.4 M stock solution. This can be calculated using the dilution formula: M1V1 = M2V2, where M1 is the concentration of the stock solution, V1 is the volume of stock solution needed, M2 is the final concentration, and V2 is the final volume.
If you mean: -6n-2n = 16 then -8n = 16 and the solution to the equation is n = -2
Use the equation; MaVa= MbVbWhere M is Molarity and V is volume.For this question, the left side of the equation is the information for 0.12M HNO3The unknown will be x on the right of the equation (replace Vb with x and solve for x).After the answer is found, it will need to be converted to mL, 1 L=1000mL
To make 6N ammonium hydroxide solution, you can dilute a concentrated solution of ammonium hydroxide with water. For example, if you have a 10N solution, you can dilute it by adding water to reduce the concentration to 6N. Make sure to use proper safety precautions when handling chemicals.