Maximum number of possible electrons in each shell:
K - 2
L - 8
M - 8
N - 18
Maximum number of electrons = 2n2, where n is the number of shell (n = 1 for K, 2 for L, 3 for M, and so on) K shell has 2 electrons maximum L shell has 8 electrons maximum M shell has 18 electrons maximum N shell has 32 electrons maximum O shell has 50 electrons maximum P shell has 72 electrons maximum
The electronic configuration of elements is determined by the energy shells k, l , m, n and so on. K is the first shell L is the second shell and so on. A shell can accommodate 2(n*n) no. of electrons where n is the no. of the shell so the first shell K can accommodate 2(1*1) electrons that is 2 electrons. The atomic no. that is the no. of protons in an atom of the element needs to be known first then as we know that protons are equal in no. to the electrons we will put 2 in K shell 8 in L shell 8 in M shell 2 in N shell then again come back to M shell and fill it to its capacity that is 2(3*3)=18 . By this way you may be able to find the configuration of the first 30 elements easily which will cover up most of the common elements found in chemical reactions.
The first shell (K shell) can hold up to 2 electrons, the second shell (L shell) can hold up to 8 electrons, the third shell (M shell) can hold up to 18 electrons, and the fourth shell (N shell) can hold up to 32 electrons.
The number of electrons that can be accommodated in an "N" shell is given by the formula 2n^2, where "n" is the principal quantum number of the shell. For example, in the third shell (n=3), the number of electrons that can be accommodated is 2(3)^2 = 18 electrons.
There are 7 different letters, each to represent each shell. They are: 1. K 2. L 3. M 4. N 5. O 6. P 7. Q
If the number of electrons in the M shell is equal to the sum of the electrons in the K and L shells, then the element is Silicon (atomic number 14). It has 4 electrons in the K shell, 8 in the L shell, and 2 in the M shell.
Maximum number of electrons = 2n2, where n is the number of shell (n = 1 for K, 2 for L, 3 for M, and so on) K shell has 2 electrons maximum L shell has 8 electrons maximum M shell has 18 electrons maximum N shell has 32 electrons maximum O shell has 50 electrons maximum P shell has 72 electrons maximum
Ammonia is a molecule (NH3) and not an atom.
Phosphorous has 2 elements in K-shell, 8 in L-shell and 5 in M-shell.
An atom of silicon has three electron shells or orbitals. These are the K, L, and M shells. The K shell can hold up to 2 electrons, the L shell can hold up to 8 electrons, and the M shell can hold up to 18 electrons.
Oxygen has 8 electrons in total. The distribution of these electrons in shells KLMN is as follows: K shell has 2 electrons, L shell has 6 electrons, M shell has 0 electrons, and N shell has 0 electrons.
the formula for finding out the maximum number of electrons is dependent upon (2n2). n represents the shell, K,L,M,N,O, etc. So if the K shell is the question K is the innermost shell and is represented as 1, so 1 squared is 1, times 2 equals 2! And L is the second shell in the orbit, so 2 squared is 4, times 2 equals 8! M is the third, so 3 squared is 9 times 2 is 18! etc....
They are named as K , L , M , N ... . Where in K is the first shell , L is the second shell , M is the third shell , N is the fourth shell and so on.
The electronic configuration of elements is determined by the energy shells k, l , m, n and so on. K is the first shell L is the second shell and so on. A shell can accommodate 2(n*n) no. of electrons where n is the no. of the shell so the first shell K can accommodate 2(1*1) electrons that is 2 electrons. The atomic no. that is the no. of protons in an atom of the element needs to be known first then as we know that protons are equal in no. to the electrons we will put 2 in K shell 8 in L shell 8 in M shell 2 in N shell then again come back to M shell and fill it to its capacity that is 2(3*3)=18 . By this way you may be able to find the configuration of the first 30 elements easily which will cover up most of the common elements found in chemical reactions.
It is because all elements in Period 3 have:2 in K- and 8 in L-shell, both completely filled up,and only 2 (out of max. 8) in the M-shell (being the outer-shell of the 3rd period for group 2).So the electron configuration should be written as:Mg(K,L,M,) = 2, 8, 2,
No, its called the K, then the L is after it and then the M and so on. On the periodic table, the period an element is in is how many electron shells it has.
I'm not sure, but I'm guessing Magnesium (Mg). On Wikipedia it says that "The electron shells are labelled K, L, M, N, O, P, and Q; or 1, 2, 3, 4, 5, 6, and 7". The first electron shell can hold 2 electrons, the second layer can hold 8, and the third layer can hold 8 as well. If we look at the question, it is practically saying, 'Your 1st and 2nd electron shells are filled (meaning there are 10 electrons so far) and there are 2 in the 3rd shell (meaning there are now 12 electrons all together). Now, if you look for the element on the Periodic Table which has an atomic number (number of protons = number of electrons) of 12, you would find Magnesium. Which should be your answer. :)