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. Use the data and the formula: 2*pi*r/p.

r is the distance of Oberon from Uranus and p is 17.24 hours. In this case r= 584,000 km. So, plugging in the values equals (knowing pi=3.14) gives you 212841.08 km/h as the velocity of the outer portion of the magnetic field just beyond Oberon.

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15y ago

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