An action potential is not passively propagated down the axon. There have to be ion channels along the axon or else the action potential will gradually decay. So the the rate of that the action potential 'travels' is dependent on the passive property called the length constant of the axon (factor in capacitance, axon diameter) plus the density of ion channels.
The conduction speed of a nerve fiber is fastest in large myelinated fibers. This is because myelin acts as an insulator, allowing for faster propagation of the action potential by saltatory conduction in large fibers compared to small unmyelinated fibers.
Myelinated nerves conduct impulses faster than unmyelinated nerves. The myelin sheath acts as an insulator that allows for faster transmission of nerve signals by increasing the speed at which the action potential travels down the axon.
I'm guessing; "myelinated nerve fibres" contrary to the much slower "non-myelinated nerve fibres"
No, the nodes of Ranvier are found at regular intervals on both myelinated central and peripheral nerve fibers. They are gaps in the myelin sheath where the axon is exposed, allowing for the propagation of action potentials along the nerve fiber.
By self regenerating, they mean that when you start an action potential, it continues in proximal (nearby) tissue (e.g., nerve). The depolarization of the action potential continues along the nerve.
The conduction speed of a nerve fiber is fastest in large myelinated fibers. This is because myelin acts as an insulator, allowing for faster propagation of the action potential by saltatory conduction in large fibers compared to small unmyelinated fibers.
In non-myelinated axons, the nerve impulse is going to be produced when the action potential accross a membrane makes a wave of depolarization followed by a wave of repolarization. With the absence of the myelin, the impulse is transmitted continuously throughout the membrane. In a non-myelinated nerve, once an end of the cell, the dendrite, is depolarized, the depolarization a.k.a., the action potential, moves along the nerve membrane, and the area of membrane immediately behind the depolarized section becomes repolarized.
Myelinated nerves conduct impulses faster than unmyelinated nerves. The myelin sheath acts as an insulator that allows for faster transmission of nerve signals by increasing the speed at which the action potential travels down the axon.
Nerve impulses travel through nerve fibers via a action potential and the speed at which the impulse travels depends on the type of nerve fibre. This can range from 100m/s in the case of touch to 20-30 m/s when you're thinking.
Unmyelinated nerve fibers conduct impulses more slowly than myelinated nerve fibers. Myelinated nerve fibers have a fatty substance called myelin sheath that allows for faster transmission of impulses compared to unmyelinated fibers without this sheath.
I'm guessing; "myelinated nerve fibres" contrary to the much slower "non-myelinated nerve fibres"
Yes, an action potential is needed for a nerve impulse to occur.
Yes, an action potential is needed for a nerve impulse to occur.
Ensure nerve impulses travel in one direction and limit the number of action potential
Myelinated nerves are white, and composes the white matter of the brain and spinal cord they also are able to pass an action potential down an axon much faster; Unmyelinated nerves are gray, and composes the gray matter of the brain and spinal cord. These nerves transmit signals much slower
No, the nodes of Ranvier are found at regular intervals on both myelinated central and peripheral nerve fibers. They are gaps in the myelin sheath where the axon is exposed, allowing for the propagation of action potentials along the nerve fiber.
Myelinated nerve fiber with a large diameter would have the fastest conduction speed. The myelin sheath allows for saltatory conduction, where the action potential jumps from one node of Ranvier to the next, speeding up conduction. A large diameter also reduces resistance to current flow, further increasing conduction speed.