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Decrease in conc. means decrease in no. of molecules per unit volume.

Since, molecules or atoms will less in number, the no. of colliding particles will be less.

This will lead to decreased precipitation

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15y ago

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How does concentration factors affect reaction rate?

increasing concentration increases rate of reaction as there are more particles so there is a larger chance of collision,it increases the probability of collision of the reactants.


How does the factor concentration affect reaction rate?

increasing concentration increases rate of reaction as there are more particles so there is a larger chance of collision,it increases the probability of collision of the reactants.


How does the concentration of reactants affect the rate of a reaction.?

Increasing the concentration increases the molecules' collision frequency.


What causes the reaction rate to decrease as the reaction progress?

The concentration of the reactants decreases.


What would most likely result in the greatest decrease in the rate of a chemical reaction?

Decreasing the temperature or changing the concentration of the reactants would most likely result in the greatest decrease in the rate of a chemical reaction. These changes affect the collision frequency and energy of the reacting molecules, slowing down the overall reaction rate.


Why does the reaction decrease as the reaction progresses?

There are fewer reactants left to collide.


Why first order reaction never completes?

A first-order reaction will never be completed because the reaction rate depends only on the concentration of one reactant. As the reaction progresses and the reactant is consumed, the concentration of the reactant decreases, causing the reaction rate to also decrease. This gradual decrease in reaction rate means that the reaction will continue indefinitely, given enough time.


What causes the reaction rate to decrease as the reaction progresses?

The concentration of the reactants decreases.


What would happen to the rate of a reaction with rate law rate k NO 2 H2 if the concentration of NO were halved?

If the concentration of NO is halved, the rate of the reaction will also be halved. This is because the rate of the reaction is directly proportional to the concentration of NO raised to the power of its coefficient in the rate law (in this case 1). So, halving the concentration of NO will result in a proportional decrease in the rate of the reaction.


What would happen to the rate of a reaction with rate law rate k NO 2 H2 if the concentration of H2 were halved?

Halving the concentration of H2 will decrease the rate of the reaction, assuming it is a first-order reaction with respect to H2. Since the rate law is rate = k[NO]^2[H2], cutting the concentration of H2 in half will decrease the rate of the reaction by a factor of 0.5.


Is it true that a low concentration of a chemical slows reaction rate?

I would point your studies towards collision theory. It's not that a low concentration necessarily slows down a reaction, but that a low concentration will have a slower reaction rate than a higher concentration of reactants. A lower concentration means a lower number of reactants in solution, meaning it is less likely for the reactants to collide and create products. With a lot of reactants, it is much more likely for collisions to occur.


What is the collision theory and how does it relates to reaction rates?

it depends on how high or low the reactant is on the temperature.