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When you decrease concentration in a reaction?
When you decrease the concentration of reactants in a chemical reaction, the reaction rate typically slows down because there are fewer reactant particles available to collide and react with each other. This aligns with the principles of collision theory, which states that reactions occur when particles collide with sufficient energy and proper orientation. Consequently, the equilibrium position may also shift to favor the formation of reactants, according to Le Chatelier's principle, if the reaction is reversible.
In a first-order reaction how does the rate change if the concentration of the reactant decreases to one-third its original value?
In a first-order reaction, the rate of reaction is directly proportional to the concentration of the reactant. If the concentration decreases to one-third of its original value, the rate of the reaction will also decrease to one-third. This is because the rate equation for a first-order reaction can be expressed as ( \text{Rate} = k[A] ), where ( k ) is the rate constant and ([A]) is the concentration of the reactant. Therefore, a decrease in concentration leads to a proportional decrease in the reaction rate.
What is the decrease in the concentration of reactants over time known as?
The decrease in the concentration of reactants over time is known as the reaction rate. This term refers to the speed at which reactants are converted into products in a chemical reaction. The reaction rate can be influenced by various factors, including temperature, concentration, and the presence of catalysts.
Why first order reaction never completes?
A first-order reaction will never be completed because the reaction rate depends only on the concentration of one reactant. As the reaction progresses and the reactant is consumed, the concentration of the reactant decreases, causing the reaction rate to also decrease. This gradual decrease in reaction rate means that the reaction will continue indefinitely, given enough time.
What would happen to the rate of a reaction with rate law rate kNO2 H2 if the concentration of no were halved?
In the given rate law, the rate of the reaction is proportional to the concentration of NO2 raised to the power of 1 and the concentration of H2 raised to the power of 1, represented as rate = k[NO2][H2]. If the concentration of NO2 is halved, the rate of the reaction would also be halved, assuming the concentration of H2 remains constant. This is because the rate directly depends on the concentration of NO2, leading to a linear decrease in the reaction rate with a decrease in its concentration.
How does concentration factors affect reaction rate?
increasing concentration increases rate of reaction as there are more particles so there is a larger chance of collision,it increases the probability of collision of the reactants.
How does the factor concentration affect reaction rate?
increasing concentration increases rate of reaction as there are more particles so there is a larger chance of collision,it increases the probability of collision of the reactants.
How does the concentration of reactants affect the rate of a reaction.?
Increasing the concentration increases the molecules' collision frequency.
What causes the reaction rate to decrease as the reaction progress?
The concentration of the reactants decreases.
What would most likely result in the greatest decrease in the rate of a chemical reaction?
Decreasing the temperature or changing the concentration of the reactants would most likely result in the greatest decrease in the rate of a chemical reaction. These changes affect the collision frequency and energy of the reacting molecules, slowing down the overall reaction rate.
When you decrease concentration in a reaction?
When you decrease the concentration of reactants in a chemical reaction, the reaction rate typically slows down because there are fewer reactant particles available to collide and react with each other. This aligns with the principles of collision theory, which states that reactions occur when particles collide with sufficient energy and proper orientation. Consequently, the equilibrium position may also shift to favor the formation of reactants, according to Le Chatelier's principle, if the reaction is reversible.
In a first-order reaction how does the rate change if the concentration of the reactant decreases to one-third its original value?
In a first-order reaction, the rate of reaction is directly proportional to the concentration of the reactant. If the concentration decreases to one-third of its original value, the rate of the reaction will also decrease to one-third. This is because the rate equation for a first-order reaction can be expressed as ( \text{Rate} = k[A] ), where ( k ) is the rate constant and ([A]) is the concentration of the reactant. Therefore, a decrease in concentration leads to a proportional decrease in the reaction rate.
What is the decrease in the concentration of reactants over time known as?
The decrease in the concentration of reactants over time is known as the reaction rate. This term refers to the speed at which reactants are converted into products in a chemical reaction. The reaction rate can be influenced by various factors, including temperature, concentration, and the presence of catalysts.
Why does the reaction decrease as the reaction progresses?
There are fewer reactants left to collide.
Why first order reaction never completes?
A first-order reaction will never be completed because the reaction rate depends only on the concentration of one reactant. As the reaction progresses and the reactant is consumed, the concentration of the reactant decreases, causing the reaction rate to also decrease. This gradual decrease in reaction rate means that the reaction will continue indefinitely, given enough time.
What would happen to the rate of a reaction with rate law rate kNO2 H2 if the concentration of no were halved?
In the given rate law, the rate of the reaction is proportional to the concentration of NO2 raised to the power of 1 and the concentration of H2 raised to the power of 1, represented as rate = k[NO2][H2]. If the concentration of NO2 is halved, the rate of the reaction would also be halved, assuming the concentration of H2 remains constant. This is because the rate directly depends on the concentration of NO2, leading to a linear decrease in the reaction rate with a decrease in its concentration.
What causes the reaction rate to decrease as the reaction progresses?
The concentration of the reactants decreases.
