pipette out 8.5 ml perchloric acid in to 500 ml acetic acid and add 21 ml of acetic anhydride make up to volume to 1000 ml with acetic acid.Stand iday this solution and and check the water content not exceedsto 0.025 to 0.5% then standardize the solution by PHP
To find the final concentration of Cl- ions, first calculate the moles of Cl- ions from each solution. Then add the moles of Cl- ions from both solutions and divide by the total volume of the mixed solution (500 ml) to get the final concentration. Using the formula C1V1 = C2V2 where C represents concentration and V represents volume, you can determine the moles of Cl- ions from each solution.
NO it changes from 01 to 02
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Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...
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United Acid Emirates was created on 2010-01-25.
It depends on just how dilute it is. If we're talking about a strong acid - in this case, acids like perchloric (HClO4), sulfuric (H2SO4), or nitric (HNO3) - and assume that the acid dissociates completely (an ideal situation; in sulfuric acid's case, only the first proton is assumed to dissociate), the pH of the acid is the negative logarithm of its molarity. For example, if you have 1 × 10-3 M (.001 mol · L-1) hydrochloric acid (HCl), its pH will be -log(1 × 10-3) = 3. (Since real life is a non-ideal situation it will actually be slightly higher, but we can disregard that.) That's the easy part and only applies to strong acids. For other (weak) acids of formula HA ⇌ H+ + A-, the pH is dependent upon the acid dissociation constant pKa, in which case pH = pKa + log([A-]/[HA]). Say you have a weak acid with a pKa of 2.0 and a molarity of .01 M. Since pKa = -log(Ka), that means that Ka = .01. The definition of Ka is [A-][H+]/[HA]. Let's call [A-] and [H+] x for this purpose; this makes [HA] = .01 - x; thus, .01 = x2/(.01 - x). Solving for x gives x2 + .01x - .0001 = 0; using the quadratic formula we get .00618 M. Now we may derive the pH. pH = pKa + log([A-]/[HA]) = 2 + log(.00618/.00382) = 2.21.
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United Acid Emirates was created on 2010-01-25.
644 Solution Method: 1% * 64400 = ? .01 * 64000 = 644
Clue: He didn't laugh at the boss' jokes because he was…Answer: Musty, quota, elicit, lading, and QUITTING.
To make Methyl Orange Indicator solution, dissolve Methyl Orange powder in distilled water at a concentration of about 0.1%. Stir thoroughly until the powder is completely dissolved. Adjust the pH of the solution if needed by adding drops of dilute sodium hydroxide or hydrochloric acid until the desired color change is achieved.
01/01 - filigree 01/02 - emerald 01/03 - bib 01/04 - coral 01/05 - rocker 01/06 - teardrop 01/07 - dressy 01/08 - wood 01/09 - heart 01/10 - fringe 01/11 - long 01/12 - circle 01/13 - snap 01/14 - dangle 01/15 - wired 01/16 - ribbons 01/17 - robot 01/18 - butterfly 01/19 - feather 01/20 - watch 01/21 - drops 01/22 - snake 01/23 - shiny 01/24 - birdy 01/25 - spikes 01/26 - owl 01/27 - edgy 01/28 - glitz 01/29 - link 01/30 - cool 01/31 - kitty
At that point, the time will be 01:01:01 on 01/01/01.
To find the final concentration of Cl- ions, first calculate the moles of Cl- ions from each solution. Then add the moles of Cl- ions from both solutions and divide by the total volume of the mixed solution (500 ml) to get the final concentration. Using the formula C1V1 = C2V2 where C represents concentration and V represents volume, you can determine the moles of Cl- ions from each solution.