How long does it take for Mercury to spin on its axis?

Answer 1

It takes about 58.6 Earth days. Mercury spins 3 times on its axis for every two revolutions around the Sun. A sidereal day on Mercury is 58.6 Earth days, at a slow equatorial rotation speed of only 10.89 km/hr.

This results in a "solar day" (time between consecutive noontimes) of two Mercury years, or 176 Earth days.

Answer 2

Mercury rotates once every 58.647 days, which is exactly 2/3 of its orbital period of 87.970 days, so it turns on its axis exactly 1 1/2 times during one of its years, causing the stars to move 1 1/2 times around the sky, each year. During that time, it moves once around the Sun, causing the Sun to appear to move backwards relative to the stars, one full turn. As a result, it has only half a day during one year (1 1/2 forward rotations by the stars, less 1 backward motion by the Sun), so that it takes two years (175.942 Earth days) for one day, three times as long as its rotation period.

Answer 3

Mercury has a rotation period of 58.66 days.

Answer 4

The rotational period of Mercury is 58.64 days which is 1407.36 hours.

Answer 5

176 days

OR

59 Earth Days = 1 Mercury Day

88 Earth Days = 1 Mercury Year

Answer 6

It can take up to 58 Earth days, 15 Earth hours, for a single rotation of the planet.

A year is only around 88 Earth Days though.

Answer 7

A long time.

It takes about 58.6 Earth days.

Answer 8

It takes about 59 Earth days for Mercury to complete one full rotation on its axis. This means that a day on Mercury (a solar day) is equivalent to about 59 Earth days.