It is 5 times the time of one half-life. Please note that different isotopes have half-lives that vary from a tiny fraction of a second to billions of years, so you can't know how long this is in days, or years, or whatever, until you know what isotope you are talking about.
91.16% of the daughter product has formed after 3.5 half lives.
If I take a radioactive sample of 400 moles of an unknown substance and let it decay to the point of three half-lives I would have 50 moles left of the sample. 1/2 of what is left will decay in the next half-life. At the end of that half-life I will have 25 moles left of the unknown substance or 4/25.
After 8.1 days, three half-lives have passed (8.1 days / 2.7 days = 3). With each half-life, the number of atoms is halved. Therefore, starting with 800 atoms, after three half-lives there would be 800 / 2 / 2 / 2 = 100 atoms remaining.
To complete 4 half lives, it would take 4 multiplied by the half-life of carbon-14. The half-life of carbon-14 is about 5,730 years, so it would take approximately 22,920 years for radioactive carbon-14 to complete 4 half lives.
When three-quarters of a radioactive isotope has decayed, it means that 1/4 (or 25%) of the original isotope remains. This corresponds to 2 half-lives, because each half-life halves the amount of radioactive material remaining.
After three half-lives, 12.5% of the radioactive isotope is remaining. This is because each half-life reduces the amount of radioactive material by half.
91.16% of the daughter product has formed after 3.5 half lives.
It will take two half-lives or about 60.34 years for three-fourths of a Cs-137 sample to decay.
For your question there could be two answers . If you meant how long a butterfly lives it is about 2 weeks if you meant actually how long a butterfly is the shortest would be a half a inch to three inches .
After three half-lives, 12.5% of the original radioactive material will remain. Each half-life reduces the amount of material by half, so after three half-lives the remaining material will be 0.5^3 = 0.125 or 12.5%.
2 half-lives have.
An eighth remains.
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.
About three days.
Not sure what you mean by "had-lives". After 3 half lives, approx 1/8 would remain.
It will take twice the half-life of the radioactive material for it to decay through two half-lives. If the half-life is 1 hour, it will take 2 hours for the material to decay through 2 half-lives.
12.5