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How many Btus must be removed from one pound of water at 200f fro it to end up as ice at 30f?
To determine the BTUs that must be removed from one pound of water at 200°F to convert it to ice at 30°F, we need to account for several steps: cooling the water from 200°F to 32°F (the freezing point), the phase change from water to ice at 32°F, and then cooling the ice from 32°F to 30°F. Cooling the water from 200°F to 32°F requires about 168 BTUs (1 BTU cools 1 pound of water by 1°F). Freezing the water at 32°F requires the removal of 80 BTUs (latent heat of fusion). Cooling the ice from 32°F to 30°F requires an additional 2 BTUs. In total, approximately 250 BTUs must be removed (168 + 80 + 2 = 250 BTUs).
How many Btus must be removed from 1lb of water at 200F for it end up as ice at 30F?
To convert 1 lb of water at 200°F to ice at 30°F, you need to remove 233 BTUs. This involves cooling the water from 200°F to 32°F (latent heat of fusion) and then further cooling the ice from 32°F to 30°F.
How many drops in one pound?
There are approximately 29,573.5 drops in one pound of water.
How many btu must be removed from one pound of water at 200F for it to end as ice at 30F?
To calculate the heat energy required to cool water from 200°F to 32°F (its freezing point) and then to further cool it to 30°F and freeze it, we need to consider the specific heat capacities and latent heat of fusion of water. The specific heat capacity of water is 1 BTU/lb°F, and the latent heat of fusion of water is 144 BTU/lb. To cool water from 200°F to 32°F, we need to remove: (200°F - 32°F) * 1 BTU/lb°F = 168 BTU. To freeze the water at 32°F, we need to remove the latent heat of fusion: 144 BTU. Therefore, the total heat energy required to cool one pound of water from 200°F to ice at 30°F is 168 BTU + 144 BTU = 312 BTU.
How many gallons of water is there in a pound of condensation?
There are a couple of problems with your question. First, "condensation" is simply water that has been changed from a vapor to a liquid, so unless you have something else in mind, your question seems to be, "How many gallons of water are there in a pound of water?" The second problem is that because there are about 8.34 pounds to a gallon of water, there are no "gallons" in a pound of water, only fractions of gallons. So, a better way to phrase your question might be, "What fraction of a gallon would a pound of water constitute?" To get the answer to that, you would simply divide one gallon by the number of pounds in a gallon (8.34) to determine that a pound of water is .12 of a gallon. Hope that helps. If that isn't what you were after, ask another question.
How many btus must be removed from one pound of water at 200 for it to end up as ice at 30?
144
How many Btu's need to be removed from lb of water to change degrees to degrees?
To change the temperature of water by one degree Fahrenheit, 1 Btu of heat must be added or removed from 1 pound of water.
How many btu's must be removed from one pound of water at 200f for it to end up as ice at 30f?
To convert water at 200°F to ice at 30°F, you need to remove 1 BTU to cool water from 200°F to 32°F to become ice. Then, you need to remove 144 BTUs to cool the ice from 32°F to 30°F. So, total BTUs needed to remove from one pound of water at 200°F to end up as ice at 30°F is 144 + 1 = 145 BTUs.
How many Btus must be removed from one pound of water at 200f fro it to end up as ice at 30f?
To determine the BTUs that must be removed from one pound of water at 200°F to convert it to ice at 30°F, we need to account for several steps: cooling the water from 200°F to 32°F (the freezing point), the phase change from water to ice at 32°F, and then cooling the ice from 32°F to 30°F. Cooling the water from 200°F to 32°F requires about 168 BTUs (1 BTU cools 1 pound of water by 1°F). Freezing the water at 32°F requires the removal of 80 BTUs (latent heat of fusion). Cooling the ice from 32°F to 30°F requires an additional 2 BTUs. In total, approximately 250 BTUs must be removed (168 + 80 + 2 = 250 BTUs).
If one pound of water is at a temperature of 32 degrees Fahrenheit, how many BTU’s must be removed in order to create a block of ice at 17 degrees?
LATENT HEAT OF FUSION When one pound of ice melts, it absorbs 144 BTUs at a constant temperature of 32°F. If one pound of water is to be frozen into ice, 144 BTUs must be removed from the water at a constant temperature of 32°F.
How many BTUs must be removed from one pound of water at 200 F for it to end up as ice at 30 F?
actually its 313.
How many btus must be removed from one pound of water at 200 degrees f for it to end up as ice at 30 degrees f?
313 Btu
How many Btus must be removed from 1lb of water at 200F for it end up as ice at 30F?
To convert 1 lb of water at 200°F to ice at 30°F, you need to remove 233 BTUs. This involves cooling the water from 200°F to 32°F (latent heat of fusion) and then further cooling the ice from 32°F to 30°F.
How many cup are in a pound?
About 2 cups in pound of water.
How many tbsp are in a pound?
There are 32 tablespoons of water in a pound.
How many btu's in office water-cooler?
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
How many 0unces in a pound of water?
There are 16 ounces in a pound. This is the same for a pound of water, lead, mud.........anything.
