How many Carbon atoms are in 0.383mg of C20H2402?

Answer 1

What kind of formula is that? You are saying, two carbons, one oxygen, twenty four hydrogen atoms and then two more oxygen atoms. C2H24O3 ??????

Remember, you asked for it, but you can follow this general form.

0.383 mg C2OH24O2 (1 gram/1000 mg)(1 mole C2OH24O2/96.212 grams)(2 mole C/1 mole C2OH24O2)(6.022 X 10^23/1 mole C)

= 4.79 X 10^18 atoms of carbon in that weird formula

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Answer 2

To find the number of Carbon atoms in C20H24O2, we first calculate the molecular weight of the compound. The molecular weight of C20H24O2 is (2012) + (241) + (2*16) = 296 g/mol. Next, we convert 0.383 mg to grams (0.383 mg = 0.000383 g) and then use the molecular weight to find the number of moles (0.000383 g / 296 g/mol = 1.293e-6 mol). Since there are 20 Carbon atoms in one molecule of C20H24O2, there are 2.59e-5 moles of Carbon atoms (1.293e-6 mol * 20). Finally, since there are 6.022e23 atoms in one mole, there are approximately 1.56e18 Carbon atoms in 0.383 mg of C20H24O2 (2.59e-5 * 6.022e23).