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What word would you use to describe HgO in the reaction that Lavoisier is used to show conservation of mass?
The word to describe HgO in Lavoisier's reaction demonstrating the conservation of mass is "reactant." In this reaction, mercury(II) oxide (HgO) decomposes upon heating into mercury (Hg) and oxygen gas (O2). Lavoisier's experiment illustrated that the total mass of the reactants (HgO) equals the total mass of the products (Hg and O2), thereby confirming the principle of conservation of mass.
How many moles of mercury (II) oxide are needed to produce 125 g of oxygen?
To determine how many moles of mercury (II) oxide (HgO) are needed to produce 125 g of oxygen (O₂), we first need to consider the decomposition reaction: 2 HgO(s) → 2 Hg(l) + O₂(g). From this equation, we see that 2 moles of HgO produce 1 mole of O₂. The molar mass of O₂ is approximately 32 g/mol, so 125 g of O₂ corresponds to about 3.91 moles (125 g ÷ 32 g/mol). Therefore, since 2 moles of HgO produce 1 mole of O₂, we need 7.82 moles of HgO (3.91 moles O₂ × 2 moles HgO/mole O₂).
How many mole is in one atom of hg?
One part of one mole of anything (eg. atoms in a mole atoms) is 1 / (6*10+23) = 1.6*10-24
How many moles of mercury are produced if 125 g of oxygen is also produced?
To determine how many moles of mercury are produced when 125 g of oxygen is generated, we first need to know the balanced chemical equation for the reaction involving mercury and oxygen. Assuming the reaction is the formation of mercury(II) oxide (HgO) from mercury (Hg) and oxygen (O₂), the equation is: 2 Hg + O₂ → 2 HgO. Given that the molar mass of oxygen (O₂) is approximately 32 g/mol, 125 g of oxygen corresponds to about 3.91 moles of O₂. According to the stoichiometry of the balanced equation, 2 moles of Hg are produced for every 1 mole of O₂. Therefore, 3.91 moles of O₂ would produce approximately 7.82 moles of Hg.
How many atoms are in 27.0 moll Hg?
To find the number of atoms in 27.0 moles of mercury (Hg), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Therefore, the total number of atoms in 27.0 moles of Hg is calculated as follows: [ 27.0 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 1.63 \times 10^{25} , \text{atoms}. ] So, there are approximately (1.63 \times 10^{25}) atoms in 27.0 moles of mercury.
How many grams of mercury are produced when 16 grams of HgO are heated?
The molar mass of Hg is 200.59 g/mol and of O is 16.00 g/mol. HgO consists of 1 Hg and 1 O atom, so the molar mass of HgO is 200.59 + 16.00 = 216.59 g/mol. To find the mass of mercury produced, we calculate the molar mass ratio of Hg to HgO: (200.59 g/mol Hg) / (216.59 g/mol HgO) = 0.926. When 16 grams of HgO are heated, the mass of mercury produced would be 16 g * 0.926 ≈ 14.82 grams.
What type of reaction is HgO - Hg plus O2?
The reaction HgO -> Hg + O2 is a decomposition reaction, where HgO breaks down into its constituent elements mercury (Hg) and oxygen gas (O2).
How many grams of mercury and oxygen are formed from 44.5g g of HgO?
To find the molar ratios of Hg and O in HgO, we need to first find the molar mass of HgO: Hg = 200.59 g/mol, O = 16.00 g/mol. HgO = 200.59 + 16.00 = 216.59 g/mol. Next, divide the mass of HgO given (44.5g) by the molar mass of HgO to find the number of moles. Then, use the mole ratio to determine the grams of mercury and oxygen formed.
What elements combine to make mercury oxide?
Mercury oxide is composed of mercury (Hg) and oxygen (O) atoms. The chemical formula for mercury(I) oxide is Hg2O, while the formula for mercury(II) oxide is HgO.
Which atoms will be found ina mercury oxide HgO is heated and decomposes?
When mercury(II) oxide (HgO) is heated, it decomposes into mercury and oxygen. The atoms present in the compound at the start of the reaction are mercury (Hg) and oxygen (O), and these same atoms will be present at the end of the reaction, just in different molecular forms.
How many atoms are there in Hg2Cl2?
There are 5 atoms in Hg2Cl2: 2 mercury atoms (Hg) and 3 chlorine atoms (Cl).
What is the formula for mercuryII oxide s?
The chemical formula for mercury(II) oxide is HgO. It is composed of one mercury (Hg) atom and one oxygen (O) atom.
What is the chemical equation for mercury two oxide?
The chemical equation for mercury(II) oxide is HgO. It is composed of one mercury (Hg) atom and one oxygen (O) atom.
What word would you use to describe HgO in the reaction that Lavoisier is used to show conservation of mass?
The word to describe HgO in Lavoisier's reaction demonstrating the conservation of mass is "reactant." In this reaction, mercury(II) oxide (HgO) decomposes upon heating into mercury (Hg) and oxygen gas (O2). Lavoisier's experiment illustrated that the total mass of the reactants (HgO) equals the total mass of the products (Hg and O2), thereby confirming the principle of conservation of mass.
Formula of mercuric oxide?
The formula for mercurous peroxide is Hg2O2.
How many atoms of (Hg) are in 200.6g and 400.1g?
The molar mass of mercury (Hg) is 200.59 g/mol. In 200.6g, there would be 1 mole of Hg, which is equal to 6.022 x 10^23 atoms. In 400.1g, there would be 2 moles of Hg, which is equal to 1.2044 x 10^24 atoms.
How many atoms are there in 0.3173 mol of Hg?
0.3173 moles Hg (6.022 X 1023/1 mole Hg) = 1.912 X 1023 atoms of mercury =======================
